用sympy解决明文中的线性方程组

I would like to add a functionality to solve systems of linear equations to my python based editor. I am looking for a module that would be able to parse a string such as the one below:

我想添加一个功能来解决线性方程组到我的基于python的编辑器。我正在寻找一个能够解析字符串的模块，如下所示：

sample_volume=20
final_concentration=0.55
ethanol_concentration=0.96

final_volume = ethanol_vol+sample_volume
final_concentration*final_volume=ethanol_vol*ethanol_concentration 

And solve for the values of all variables.

并解决所有变量的值。

I have implemented a quick and dirty script using sympy that does this, see here for a Jupyter notebook.

我已经使用sympy实现了一个快速而肮脏的脚本，请参阅此处查看Jupyter笔记本。

I think that this must have been implemented by someone in a more robust way, I would like to avoid reinventing the wheel here.

我认为这必须以更强大的方式实施，我想避免在这里重新发明*。

Does anyone know of any alternative implementation that are more robust (have tests etc)?

有没有人知道任何更强大的替代实现（有测试等）？

Additionally, according to the sympy docs, sympy.solveset should be used instead of sympy.solve. I cannot make this work with a list of equations as in my example. Can someone proficient in sympy guide me how to use solveset with an equation system such as this.

另外，根据sympy docs，应该使用sympy.solveset而不是sympy.solve。我不能用我的例子中的方程列表来完成这项工作。精通同情的人可以指导我如何使用像这样的方程系统来解决问题。

1 个解决方案

#1

In [2]: sample_volume=20
   ...: final_concentration=0.55
   ...: ethanol_concentration=0.96
   ...: 

In [4]: fv,ev = symbols('fv,ev')

In [5]: expr1 = fv - ev+sample_volume

In [6]: expr2 = final_concentration*fv - ev*ethanol_concentration 

In [7]: solve([expr1,expr2], [fv,ev])
Out[7]: {ev: -26.8292682926829, fv: -46.8292682926829}

# I will recommend to use solveset's linear system solver (linsolve)
In [8]: linsolve([expr1,expr2], [fv,ev])
Out[8]: {(-46.8292682926829, -26.8292682926829)}