TypeError: 'int'对象不可迭代

I am trying to have a program look inside multiple lists to see if there are multiple integers in those lists. I received an answer on a previous question I asked to accomplish that task. However a problem arose with that answer and I can not figure out what it is.

我正在尝试让一个程序查看多个列表，看看这些列表中是否有多个整数。为了完成这项任务，我曾问过一个问题。然而，这个答案产生了一个问题，我想不出它是什么。

Here is the code:

这是代码:

def all_num_in_list(d, numbers):
    for n in numbers:
        if n not in d:
            return False
    return True
def all_num_in_any_list(lists, numbers):
    for d in lists:
        if all_num_in_list(d, numbers):
            return True
    return False
while a:
    try:
        for c, row in enumerate(matrix):
            if 0 in row:
                print("Found 0 on row:", c, "index:", row.index(0))
                if 1 not in row:
                    if all(row[row.index(0)] != 1 for row in matrix):
                        if all_num_in_any_list([2, 3, 4, 5, 6, 7, 8, 9], [row, box1, all(row[row.index(0)])]):
                        if all(row[row.index(0)] != 1 for row in matrix):
                            print ("t")

The error that it draws is:

它绘制的错误是:

if all_num_in_any_list([2, 3, 4, 5, 6, 7, 8, 9], [row, box1, all(row[row.index(0)])]):
TypeError: 'int' object is not iterable

Why is this happening, how can it be avoided, and what exactly is this code doing?

为什么会发生这种情况，如何避免这种情况，代码到底在做什么?

Thanks

谢谢

4 个解决方案

#1

The first parameter to all_num_in_any_list, [2,3,4,5,6,7,8,9], is a single list, not a list of lists. When you iterate through it, d is 1, then d is 2, and so forth. When you pass d as the first parameter to all_num_in_list, it is trying to treat it as a list even though it is an integer.

all_num_in_any_list的第一个参数是一个列表，而不是一个列表列表。当你迭代它时，d是1，然后d是2，以此类推。当您将d作为第一个参数传递给all_num_in_list时，它试图将它作为一个列表来处理，即使它是一个整数。

#2

Here is your matrix, from an earlier question

这是你的矩阵，从之前的一个问题。

matrix = [
    [0, 0, 0, 5, 0, 0, 0, 0, 6],
    [8, 0, 0, 0, 4, 7, 5, 0, 3],
    [0, 5, 0, 0, 0, 3, 0, 0, 0],
    [0, 7, 0, 8, 0, 0, 0, 0, 9],
    [0, 0, 0, 0, 1, 0, 0, 0, 0],
    [9, 0, 0, 0, 0, 4, 0, 2, 0],
    [0, 0, 0, 9, 0, 0, 0, 1, 0],
    [7, 0, 8, 3, 2, 0, 0, 0, 5],
    [3, 0, 0, 0, 0, 8, 0, 0, 0],
    ]

And here is the methods:

这里有一些方法:

def all_num_in_list(d, numbers):
    for n in numbers:
        if n not in d:
            return False
    return True

def all_num_in_any_list(lists, numbers):
    for d in lists:
        if all_num_in_list(d, numbers):
            return True
    return False

And since you in an earlier question used the numbers, 3,5 and 6 as examples to look at, here is how you check if these numbers are in the matrix above:

由于你在之前的问题中使用了数字3 5 6作为例子，这是你如何检查这些数字是否在上面的矩阵中:

all_num_in_any_list(matrix, [3, 5, 6])

Which will return False, as none of the lists in your list of lists will have all these tree numbers, while for example:

返回False，因为列表中的列表中没有一个列表包含所有这些树号，例如:

all_num_in_any_list(matrix, [0, 1, 9])

will return True, as there is a list that includes these numbers.

将返回True，因为有一个包含这些数字的列表。

#3

all_num_in_any_list extacts elements from lists, which in this case are all integers; then, it passes each integer to all_num_in_list, which is expecting a list instead.

all_num_in_any_list扩展列表中的元素，在本例中这些元素都是整数;然后，它将每个整数传递给all_num_in_list，后者期望得到一个列表。

#4

The statement for n in numbers in this code is causing the problem

这个代码中的n的语句导致了这个问题。

def all_num_in_list(d, numbers):      
    for n in numbers:          
        if n not in d:              
            return False      
    return True

The Partial Traceback is

部分回溯是

if n not in d
def all_num_in_list(d, numbers):
def all_num_in_any_list(lists, numbers):
if all_num_in_any_list([2, 3, 4, 5, 6, 7, 8, 9], [row, box1, all(row[row.index(0)])]):        
TypeError: 'int' object is not iterable

So in function all_num_in_any_list you are already iterating for d in lists over the list lists to get integers which is passed to all_num_in_list. But here while trying to compare n with an atom d, is where the Error Happened.

因此，在函数all_num_in_any_list中，您已经在列表列表中迭代了d，以获得传递到all_num_in_list的整数。但是在这里，当试图比较n和一个原子d时，错误发生了。

Think Over?

想结束了吗?

Did you intend to do an integer comparition like n != d instead of if n not in d .

你想做一个像n != d这样的整数比较而不是如果n不在d中。

Note::: Next Time please post the Complete Traceback

注:::下次请张贴完整的回溯

#1

#2