53. Maximum Subarray

时间:2022-09-12 19:13:06

Find the contiguous subarray within an array (containing at least one number) which has the largest sum.

For example, given the array [−2,1,−3,4,−1,2,1,−5,4],
the contiguous subarray [4,−1,2,1] has the largest sum = 6.

click to show more practice.

More practice:

If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.

=====================
状态转移方程为:
/**dp
        f[i] = max{f[i-1]+nums[i],nums[i]},1<=i<n
        return max{f[i]} 0<=i<n
        */
---------
=========
code
class Solution {
public:
int maxSubArray(vector<int> &nums){
/**dp
f[i] = max{f[i-1]+nums[i],nums[i]},1<=i<n
return max{f[i]} 0<=i<n
*/ int length = nums.size();
vector<int> f(length);
f[] = nums[];
for(int i = ;i<length;i++){
f[i] = max(f[i-]+nums[i],nums[i]);
} vector<int>::iterator iter;
iter = max_element(f.begin(),f.end());
return *iter;
}
};