leetcode答案-easy_Maximum-Subarray:easy_Maximum-Subarray

时间:2024-07-19 18:47:23
【文件属性】:

文件名称:leetcode答案-easy_Maximum-Subarray:easy_Maximum-Subarray

文件大小:4KB

文件格式:ZIP

更新时间:2024-07-19 18:47:23

系统开源

leetcode 答案 easy_Maximum-Subarray 提交链接 / Submit (You need register/login first before submit.) (在提交前你需要先注册或登录) 题目描述 / Description Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum. 给定一个整数数组 nums ,找到一个具有最大和的连续子数组(子数组最少包含一个元素),返回其最大和。 Bonus: If you have realized the solution with O(n), try something more tricky than standard program by divide-and-conquer method. 附加:如果你已经实现为 O(n) 的解法,尝试使用比标准程序更为精妙的分治法求解。 输入 / Inpu


【文件预览】:
easy_Maximum-Subarray-master
----README.md(3KB)
----solve.c(1KB)
----solve.py(427B)
----solve.cpp(1024B)

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