Python numpy如何从数组连接数字

I am newbie in Python. I think I'm looking for something easy, but can't find. I have an numpy binary array, e.g.:

我是Python的新手。我想我正在寻找一些容易的东西,却找不到。我有一个numpy二进制数组,例如:

 [1,0,1,1,0,0,0,1,1,1,1,0]

And I want to do 2 things:

我想做两件事:

Join (?) all elements into one number, so result will be:

将(?)所有元素加入一个数字,结果将是:
```
x=101100011110
```
Next want to converse it into binary, so:

接下来想把它转换成二进制,所以:
```
xx=2846
```

I have an algorithm to do 2., but I don't know how to do 1. I can do it using loop, but is it possible to do it using numpy, without loop? My array will be huge, so I need the best option.

我有一个算法做2.但我不知道该怎么做1.我可以使用循环来做,但是可以使用numpy,没有循环吗?我的阵列很大,所以我需要最好的选择。

3 个解决方案

#1

>>> int(''.join(map(str, [1,0,1,1,0,0,0,1,1,1,1,0])))
101100011110

Or with a little numpy:

或者有点numpy:

>>> int(''.join(np.array([1,0,1,1,0,0,0,1,1,1,1,0]).astype('|S1')))
101100011110

#2

I like @timgeb's answer, but if you're sure you want to use numpy calculations directly, you could do something like this:

我喜欢@ timgeb的答案,但是如果你确定要直接使用numpy计算,你可以这样做:

x = np.array([1,0,1,1,0,0,0,1,1,1,1,0])
exponents = np.arange(len(x))[::-1]
powers = 10**exponents
result = sum(powers * x)

In [12]: result
Out[12]: 101100011110

As pointed out by @Magellan88 in the comments, if you set powers=2**exponents you can get from 0 to your second part of the question in one sweep.

正如@ Magellan88在评论中指出的那样,如果你设置powers = 2 **指数,你可以在一次扫描中从0到你问题的第二部分。

#3

Since you don't want loop in first task then you can go with map method , I just wanted to show you can also try this :

既然你不想在第一个任务中循环,那么你可以使用map方法,我只是想表明你也可以试试这个:

import numpy as np
array=np.array([1,0,1,1,0,0,0,1,1,1,1,0])

int_con=str(array).replace(',','').replace(' ','').replace('[','').replace(']','')

print("Joined {}".format(int_con))

bin_to_de=0

for digit in int_con:
    bin_to_de=bin_to_de*2+int(digit)

print("Decimal conversion {}".format(bin_to_de))

output:

Joined 101100011110
Decimal conversion 2846

#1

>>> int(''.join(map(str, [1,0,1,1,0,0,0,1,1,1,1,0])))
101100011110