I want to do replace for the following patterns (the foregoing rule has higher priority)
我想替换以下模式(上述规则具有更高的优先级)
\right) -> remain unchanged
\right ) -> remain unchanged
\right] -> remain unchanged
\right ] -> remain unchanged
\right} -> remain unchanged
\right } -> remain unchanged
\ri) -> \right)
\ri -> \rightarrow
\right -> \rightarrow
In other words, if there is any parentheses bracket or brace, I want to have \right, if anything else, it should be replaced by \rightarrow. In short, I was trying transform a lot of shorthanded google doc equations with into proper LaTeX format. What I came up with was the following
换句话说,如果有任何括号括号或括号,我想要\ right,如果有的话,它应该被\ rightarrow替换。简而言之,我正在尝试将大量短缺的google doc方程转换为适当的LaTeX格式。我想出的是以下内容
sed -i 's/\\ri\([^g]\)/\\right\1/g' $tempfile1 #first step substitution
sed -i 's/\\right\([^])}>|a]\)/\\rightarrow\1/g' $tempfile1
sed -i 's/\\right \([^])}>|a]\)/\\rightarrow \1/g' $tempfile1
It works ok except it does not change \right\ into \rightarrow\ as expected. My test input tempfile1 is the following
它工作正常,但它不会按预期更改\ right \ into \ rightarrow \。我的测试输入tempfile1如下
\ri\right\right \right)\right]\right }\right )\ri \right ]\righta \al \\
It goes into
它进入了
\rightarrow\right\rightarrow \right)\right]\right }\right )\rightarrow \right ]\rightarrow \alpha \\
Noting that the \right\ part was not done correctly. Then I added the following line, thinking that it will explicit pick up what was left, however, it does not work as expected and now I am really confused...
注意到\ right \ part没有正确完成。然后我添加了以下一行,认为它会明确地拿起剩下的东西,然而,它没有按预期工作,现在我真的很困惑......
sed -i 's/\\right\\/\\rightarrow\\/g' $tempfile1 #why this does not work
Thanks a lot in advance!
非常感谢提前!
1 个解决方案
#1
3
The trouble occurs when the expression:
表达式出现问题:
sed -i 's/\\right\([^])}>|a]\)/\\rightarrow\1/g'
is applied to:
适用于:
\right\right\
The first match reads \right\ and replaces it with \rightarrow\; the problem occurs when the scan resumes, it starts at the r of the second right, not with the backslash (that was part of the previous match).
第一个匹配读取\ right \并用\ rightarrow \替换它;扫描恢复时出现问题,它从第二个右边的r开始,而不是反斜杠(这是前一个匹配的一部分)。
The simple trick is to repeat the command...
简单的诀窍是重复命令......
sed -i -e 's/\\right\([^])}>|a]\)/\\rightarrow\1/g' \
-e 's/\\right\([^])}>|a]\)/\\rightarrow\1/g'
The rescan deals with the second \right\ sequence by starting ab initio again.
重新扫描通过再次启动ab initio来处理第二个\ right \序列。
#1
3
The trouble occurs when the expression:
表达式出现问题:
sed -i 's/\\right\([^])}>|a]\)/\\rightarrow\1/g'
is applied to:
适用于:
\right\right\
The first match reads \right\ and replaces it with \rightarrow\; the problem occurs when the scan resumes, it starts at the r of the second right, not with the backslash (that was part of the previous match).
第一个匹配读取\ right \并用\ rightarrow \替换它;扫描恢复时出现问题,它从第二个右边的r开始,而不是反斜杠(这是前一个匹配的一部分)。
The simple trick is to repeat the command...
简单的诀窍是重复命令......
sed -i -e 's/\\right\([^])}>|a]\)/\\rightarrow\1/g' \
-e 's/\\right\([^])}>|a]\)/\\rightarrow\1/g'
The rescan deals with the second \right\ sequence by starting ab initio again.
重新扫描通过再次启动ab initio来处理第二个\ right \序列。