I am trying to replace the space before the surname on each line of a file with a comma using sed.
我试图用逗号使用sed替换文件每行上的姓氏前的空格。
Example Source:
George W Heong§New York§USA
Elizabeth Black§Sheffield, Yorkshire§England
Lucy Jones§Cardiff§Wales
James G K Shackleton§Dallas, Texas§USA
Carl Seddon§Canberra,Australia
Example Ouput:
George W,Heong§New York§USA
Elizabeth,Black§Sheffield, Yorkshire§England
Lucy,Jones§Cardiff§Wales
James G K,Shackleton§Dallas, Texas§USA
Carl,Seddon§Canberra,Australia
I think I've worked out a method to obtain the index of the relevant space as follows:
我想我已经找到了一种获取相关空间索引的方法,如下所示:
int idx$ = str.indexOf("§");
int nthSpace = str.lastIndexOf(" ", idx$);
but I haven't been able to work out how to replace the nth instance with the variable nthSpace. This is what have got so far:
但我还没有弄清楚如何用变量nthSpace替换第n个实例。这是到目前为止:
sed "s/$nthSpace" "/,/" datain.txt > dataout.txt
Any asistance would be appreciated.
任何援助将不胜感激。
2 个解决方案
#1
1
With sed :
用sed:
sed 's/ \([^ ]*§\)/,\1/' sourcefile
The pattern looks for the first occurence of :
该模式寻找第一次出现:
- a space
- followed by any non-space char
- followed by §
然后是任何非空格字符
其次是 §
The name is captured in a group that is used in the substitution to be prefixed with a ,
该名称在一个用于替换的组中捕获,该组以a为前缀,
UPDATE :
To prevent strings as name §
to be matched, you can preprocess the first substitution with s/ +§/§/
. The final command will be :
要防止匹配名称§的字符串,可以使用s / +§/§/预处理第一个替换。最后的命令是:
sed 's/ +§/§/;s/ \([^ ]*§\)/,\1/' sourcefile
As noticed in question comments, multipart surnames (separated with spaces) will be split if not rewritten manually.
正如在问题评论中注意到的那样,如果不手动重写,多部分姓氏(用空格分隔)将被拆分。
#2
1
With gensub
, available in GNU awk
, you can do this:
使用GNU awk中提供的gensub,您可以执行以下操作:
awk 'BEGIN{FS=OFS="§"} {$1=gensub(/[[:blank:]]([^[:blank:]]+)$/, ",\\1", 1, $1)} 1' file
Output:
George W,Heong§New York§USA
Elizabeth,Black§Sheffield, Yorkshire§England
Lucy,Jones§Cardiff§Wales
James G K,Shackleton§Dallas, Texas§USA
Carl,Seddon§Canberra,Australia
#1
1
With sed :
用sed:
sed 's/ \([^ ]*§\)/,\1/' sourcefile
The pattern looks for the first occurence of :
该模式寻找第一次出现:
- a space
- followed by any non-space char
- followed by §
然后是任何非空格字符
其次是 §
The name is captured in a group that is used in the substitution to be prefixed with a ,
该名称在一个用于替换的组中捕获,该组以a为前缀,
UPDATE :
To prevent strings as name §
to be matched, you can preprocess the first substitution with s/ +§/§/
. The final command will be :
要防止匹配名称§的字符串,可以使用s / +§/§/预处理第一个替换。最后的命令是:
sed 's/ +§/§/;s/ \([^ ]*§\)/,\1/' sourcefile
As noticed in question comments, multipart surnames (separated with spaces) will be split if not rewritten manually.
正如在问题评论中注意到的那样,如果不手动重写,多部分姓氏(用空格分隔)将被拆分。
#2
1
With gensub
, available in GNU awk
, you can do this:
使用GNU awk中提供的gensub,您可以执行以下操作:
awk 'BEGIN{FS=OFS="§"} {$1=gensub(/[[:blank:]]([^[:blank:]]+)$/, ",\\1", 1, $1)} 1' file
Output:
George W,Heong§New York§USA
Elizabeth,Black§Sheffield, Yorkshire§England
Lucy,Jones§Cardiff§Wales
James G K,Shackleton§Dallas, Texas§USA
Carl,Seddon§Canberra,Australia