I'm trying to escape the characters -]\^$*.
each with a single backslash \
.
我试图逃避角色 - ] \ ^ $ *。每个都有一个反斜杠\。
For example the string: ^stack.*/overflo\w$arr=1
will become:
例如字符串:^ stack。* / overflo \ w $ arr = 1将变为:
\^stack\.\*/overflo\\w\$arr=1
What's the most efficient way to do that in Python?
在Python中最有效的方法是什么?
re.escape
double escapes which isn't what I want:
re.escape double escapes这不是我想要的:
'\\^stack\\.\\*\\/overflow\\$arr\\=1'
I need this to escape for something else (nginx).
我需要这个以逃避其他东西(nginx)。
5 个解决方案
#1
57
This is one way to do it (in Python 3.x):
这是一种方法(在Python 3.x中):
escaped = a_string.translate(str.maketrans({"-": r"\-",
"]": r"\]",
"\\": r"\\",
"^": r"\^",
"$": r"\$",
"*": r"\*",
".": r"\."}))
For reference, for escaping strings to use in regex:
作为参考,用于转义在正则表达式中使用的字符串:
import re
escaped = re.escape(a_string)
#3
4
Simply using re.sub
might also work instead of str.maketrans
. And this would also work in python 2.x
简单地使用re.sub也可以代替str.maketrans。这也适用于python 2.x.
>>> print(re.sub(r'(\-|\]|\^|\$|\*|\.|\\)',lambda m:{'-':'\-',']':'\]','\\':'\\\\','^':'\^','$':'\$','*':'\*','.':'\.'}[m.group()],"^stack.*/overflo\w$arr=1"))
\^stack\.\*/overflo\\w\$arr=1
#4
4
re.escape
doesn't double escape. It just looks like it does if you run in the repl. The second layer of escaping is caused by outputting to the screen.
re.escape不会双重逃脱。如果你在repl中运行它看起来就像它。第二层转义是由输出到屏幕引起的。
When using the repl, try using print
to see what is really in the string.
使用repl时,尝试使用print来查看字符串中的内容。
$ python
>>> import re
>>> re.escape("\^stack\.\*/overflo\\w\$arr=1")
'\\\\\\^stack\\\\\\.\\\\\\*\\/overflo\\\\w\\\\\\$arr\\=1'
>>> print re.escape("\^stack\.\*/overflo\\w\$arr=1")
\\\^stack\\\.\\\*\/overflo\\w\\\$arr\=1
>>>
#5
0
Utilize the output of built-in repr
to deal with \r\n\t
and process the output of re.escape
is what you want:
利用内置repr的输出来处理\ r \ n \ t并处理re.escape的输出是你想要的:
re.escape(repr(a)[1:-1]).replace('\\\\', '\\')
#1
57
This is one way to do it (in Python 3.x):
这是一种方法(在Python 3.x中):
escaped = a_string.translate(str.maketrans({"-": r"\-",
"]": r"\]",
"\\": r"\\",
"^": r"\^",
"$": r"\$",
"*": r"\*",
".": r"\."}))
For reference, for escaping strings to use in regex:
作为参考,用于转义在正则表达式中使用的字符串:
import re
escaped = re.escape(a_string)
#2
#3
4
Simply using re.sub
might also work instead of str.maketrans
. And this would also work in python 2.x
简单地使用re.sub也可以代替str.maketrans。这也适用于python 2.x.
>>> print(re.sub(r'(\-|\]|\^|\$|\*|\.|\\)',lambda m:{'-':'\-',']':'\]','\\':'\\\\','^':'\^','$':'\$','*':'\*','.':'\.'}[m.group()],"^stack.*/overflo\w$arr=1"))
\^stack\.\*/overflo\\w\$arr=1
#4
4
re.escape
doesn't double escape. It just looks like it does if you run in the repl. The second layer of escaping is caused by outputting to the screen.
re.escape不会双重逃脱。如果你在repl中运行它看起来就像它。第二层转义是由输出到屏幕引起的。
When using the repl, try using print
to see what is really in the string.
使用repl时,尝试使用print来查看字符串中的内容。
$ python
>>> import re
>>> re.escape("\^stack\.\*/overflo\\w\$arr=1")
'\\\\\\^stack\\\\\\.\\\\\\*\\/overflo\\\\w\\\\\\$arr\\=1'
>>> print re.escape("\^stack\.\*/overflo\\w\$arr=1")
\\\^stack\\\.\\\*\/overflo\\w\\\$arr\=1
>>>
#5
0
Utilize the output of built-in repr
to deal with \r\n\t
and process the output of re.escape
is what you want:
利用内置repr的输出来处理\ r \ n \ t并处理re.escape的输出是你想要的:
re.escape(repr(a)[1:-1]).replace('\\\\', '\\')