如何在XML文件中的特定节点的第一个和最后一个之间获取？

Consider I have a file which contains the following data:

考虑我有一个包含以下数据的文件：

  ...
    <wsdl:message>
      ...
    </wsdl:message>
    <wsdl:message>
      ...
    </wsdl:message>
    <wsdl:message>
      ...
    </wsdl:message>
  ...

What would be an appropriate regex to get all data between the first <wsdl:message> and the last </wsdl:message>?

在第一个和最后一个之间获取所有数据的适当正则表达式是什么？：message>

Or alternatively, (as has been suggested), an appropriate XPath solution.

或者，（如已建议的那样），一个适当的XPath解决方案。

The main idea is that I would like to find and replace that portion of data.

主要想法是我想找到并替换那部分数据。

2 个解决方案

#1

Just use:

只需使用：

//x:message/node()

where the prefix x: is bound (in the programming language that is hosting XPath) to the wsdl namespace -- this is often called "registering a namespace").

其中前缀x：绑定（以托管XPath的编程语言）到wsdl命名空间 - 这通常称为“注册命名空间”）。

Alternatively, if you aren't able to register this namespace, use:

或者，如果您无法注册此命名空间，请使用：

//*[local-name()='message' 
  and 
    namespace-uri() = 'http://schemas.xmlsoap.org/wsdl/'
    ]/node()

#2

The XPath

XPath

/*/wsdl:message[fn:position() > 1 and fn:position() < fn:last()]

should do it.

应该这样做。

EDIT

编辑

For XPath 1.0 (and code for PHP)

对于XPath 1.0（和PHP的代码）

<?php
$string = <<<XML
<?xml version="1.0" encoding="utf-8"?>
<root xmlns:wsdl="/">
    <wsdl:message> 
      One
    </wsdl:message> 
    <wsdl:message> 
      Two 
    </wsdl:message> 
    <wsdl:message> 
      Three 
    </wsdl:message> 
    <wsdl:message> 
      Four 
    </wsdl:message> 
    <wsdl:message> 
      Five 
    </wsdl:message> 
    <wsdl:message> 
      Six 
    </wsdl:message>
</root>
XML;

print $string;
$xml = new SimpleXMLElement($string);

print_r($xml->xpath('/*/wsdl:message[position() > 1'.
                    ' and position() < last()]'));

?>

#1