If I have an array of doubles:
如果我有一个双精度的数组:
[10.2, 20, 11.1, 21, 31, 12, 22.5, 32, 42, 13.6, 23, 32, 43.3, 53, 14, 24, 34, 44, 54, 64, 15.1, 25, 35, 45, 55, 65.3, 75.4, 16, 26, 17.5,]
and I want to get the first element and last element so that
我想要得到第一个元素和最后一个元素
firstNum = 10.2
lastNum = 17.5
how would I do this?
我该怎么做呢?
3 个解决方案
#1
20
If you have a double array named numbers, you can use:
如果你有一个双数组命名的数字，你可以使用:
firstNum = numbers[0];
lastNum = numbers[numbers.length-1];
#2
3
// Array of doubles
double[] array_doubles = {2.5, 6.2, 8.2, 4846.354, 9.6};
// First position
double firstNum = array_doubles[0]; // 2.5
// Last position
double lastNum = array_doubles[array_doubles.length - 1]; // 9.6
This is the same in any array.
这在任何数组中都是一样的。
#3
0
Check this
检查这个
double[] myarray = ...;
System.out.println(myarray[myarray.length-1]); //last
System.out.println(myarray[0]); //first
#1
20
If you have a double array named numbers, you can use:
如果你有一个双数组命名的数字，你可以使用:
firstNum = numbers[0];
lastNum = numbers[numbers.length-1];
#2
3
// Array of doubles
double[] array_doubles = {2.5, 6.2, 8.2, 4846.354, 9.6};
// First position
double firstNum = array_doubles[0]; // 2.5
// Last position
double lastNum = array_doubles[array_doubles.length - 1]; // 9.6
This is the same in any array.
这在任何数组中都是一样的。
#3
0
Check this
检查这个
double[] myarray = ...;
System.out.println(myarray[myarray.length-1]); //last
System.out.println(myarray[0]); //first