So I have this array:
所以我有这个数组:
[0] => 3
[1] => 9
[2] => 4
[3] => 6
[4] => 69
[5] => 8
[6] => 9
[7] => 12
[8] => 9
[9] => 7
And this one
这一个
[Far] => 1
[far] => 3
[away] => 1
[behind] => 1
[the] => 23
[word] => 2
[mountains] => 1
[from] => 3
[countries] => 1
[Vokalia] => 1
I would like that the values of the first array will overwrite the values of the second array without changing the keys of the second array. I have already tried fiddling with the foreach function, but no prevail. So in the end I would like it to look like this:
我希望第一个数组的值将覆盖第二个数组的值，而不更改第二个数组的键。我已经尝试过修改foreach函数，但是没有成功。最后我希望它是这样的:
[Far] => 3
[far] => 9
[away] => 4
[behind] => 6
[the] => 69
[word] => 8
[mountains] => 9
[from] => 12
[countries] => 9
[Vokalia] => 7
does anyone know how to do that? And if yes, can that person give a bit more information how it works in the foreach function?
有人知道怎么做吗?如果是，那个人能提供更多关于foreach函数的信息吗?
1 个解决方案
#1
5
Assuming your arrays are $array1 and $array2:
假设数组为$array1和$array2:
$keys = array_keys($array2);
$result = array_combine($keys, $array1);
Documentation:
文档:
array_keys()- 中的()
array_combine()- 合二为一()
在线演示
#1
5
Assuming your arrays are $array1 and $array2:
假设数组为$array1和$array2:
$keys = array_keys($array2);
$result = array_combine($keys, $array1);
Documentation:
文档:
array_keys()- 中的()
array_combine()- 合二为一()
在线演示