hdu 4750 Count The Pairs(并查集)

时间:2021-09-25 07:59:50

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4750

代码:

#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std; const int maxn = ;
const int maxm = ; struct Edge
{
int u,v,w;
Edge(int u=,int v=,int w=): u(u), v(v), w(w) {}
bool operator < (const Edge& rhs) const
{
return w < rhs.w;
}
}edges[maxm];
struct Query
{
int id;
int num;
bool operator < (const Query& rhs) const
{
return num < rhs.num;
}
}Q[maxn*]; int pa[maxn];
int counts[maxn];
int ans[maxn*]; int find(int x)
{
return x == pa[x] ? x : pa[x] = find(pa[x]);
} int main()
{
//freopen("E:\\acm\\input.txt","r",stdin);
int n,m,p;
while(cin>>n>>m)
{
for(int i=; i<n; i++)
{
pa[i] = i;
counts[i] = ;
}
for(int i=; i<m; i++)
{
int a,b,c;
scanf("%d %d %d",&a,&b,&c);
edges[i] = Edge(a,b,c);
}
sort(edges,edges+m); scanf("%d",&p);
for(int i=; i<p; i++)
{
scanf("%d",&Q[i].num);
Q[i].id = i;
}
sort(Q,Q+p); int cnt = ;
int sum = ;
int tot = n*(n-); //这么做前提是图是连通的,只能样例给的是连通的 for(int i=; i<p; i++)
{
while(cnt<m && edges[cnt].w < Q[i].num)
{
int u_fa = find(edges[cnt].u);
int v_fa = find(edges[cnt].v);
if(u_fa != v_fa)
{
sum = sum + counts[u_fa]*counts[v_fa]*;
pa[v_fa] = u_fa;
counts[u_fa] += counts[v_fa];
}
cnt++;
} ans[Q[i].id] = tot - sum;
}
for(int i=; i<p; i++)
printf("%d\n",ans[i]);
}
}