Swig [C-> Python]：如何处理作为原始类型的输入或输出函数参数？

for example, I have

例如,我有

my_types.h

typedef uint16_t my_type_1;
typedef uint8_t my_type_2;

my_types.c

int my_func(my_type_1 * arg1, my_type_2 * arg2, my_type_3 *arg3)
{
    *args3 = *arg1 + *arg2;
    return 0;
}

how do I define the interface file to have this wrapped to python?

如何定义接口文件以将其包装为python?

1 个解决方案

#1

Assuming you don't have a declaration of my_func in my_types.h as well then your interface can become:

假设你在my_types.h中没有my_func的声明,那么你的界面可以变成:

%module test

%{
#include "my_types.h"
%}

%include <stdint.i>

%include "my_types.h"

%apply uint16_t *INPUT { my_type_1 * arg1 };
%apply uint8_t *INPUT { my_type_2 * arg2 };
%apply uint16_t *OUTPUT { my_type_1 *arg3 };

int my_func(my_type_1 * arg1, my_type_2 * arg2, my_type_1 *arg3);

This is sufficient to allow you to use it as follows:

这足以让您按如下方式使用它:

import test

print test.my_func(100, 50)[1]

Your "real" return is position 0 in the tuple, the first OUTPUT is at position 1.

您的“真实”返回是元组中的位置0,第一个OUTPUT位于位置1。

#1