使用AJAX将变量传递给PHP并再次使用AJAX检索它们

I want to pass values to a PHP script so i am using AJAX to pass those, and in the same function I am using another AJAX to retrieve those values.

我想将值传递给PHP脚本，所以我使用AJAX传递它们，并且在同一个函数中我使用另一个AJAX来检索这些值。

The problem is that the second AJAX is not retrieving any value from the PHP file. Why is this? How can I store the variable passed on to the PHP script so that the second AJAX can retrieve it?

问题是第二个AJAX没有从PHP文件中检索任何值。为什么是这样？如何将传递给PHP脚本的变量存储起来，以便第二个AJAX可以检索它？

My code is as follows:

我的代码如下：

AJAX CODE:

AJAX代码：

$(document).ready(function() {    
    $("#raaagh").click(function(){    
        $.ajax({
            url: 'ajax.php', //This is the current doc
            type: "POST",
            data: ({name: 145}),
            success: function(data){
                console.log(data);
            }
        });  
        $.ajax({
            url:'ajax.php',
            data:"",
            dataType:'json',
            success:function(data1){
                var y1=data1;
                console.log(data1);
            }
        });
    });
});

PHP CODE:

PHP代码：

<?php
$userAnswer = $_POST['name'];    
echo json_encode($userAnswer);    
?>

5 个解决方案

#1

Use dataType:"json" for json data

对于json数据，请使用dataType：“json”

$.ajax({
     url: 'ajax.php', //This is the current doc
     type: "POST",
     dataType:'json', // add json datatype to get json
     data: ({name: 145}),
     success: function(data){
         console.log(data);
     }
});

Read Docs http://api.jquery.com/jQuery.ajax/

阅读文档http://api.jquery.com/jQuery.ajax/

Also in PHP

还有PHP

<?php
  $userAnswer = $_POST['name']; 
  $sql="SELECT * FROM <tablename> where color='".$userAnswer."'" ;
  $result=mysql_query($sql);
  $row=mysql_fetch_array($result);
  // for first row only and suppose table having data
  echo json_encode($row);  // pass array in json_encode  
?>

#2

No need to use second ajax function, you can get it back on success inside a function, another issue here is you don't know when the first ajax call finished, then, even if you use SESSION you may not get it within second AJAX call.

不需要使用第二个ajax函数，你可以在函数内取回成功，这里的另一个问题是你不知道第一个ajax调用何时完成，那么，即使你使用SESSION你可能也不会在第二个AJAX中得到它呼叫。

SO, I recommend using one AJAX call and get the value with success.

所以，我建议使用一个AJAX调用并获得成功的价值。

example: in first ajax call

例如：在第一次ajax调用中

    $.ajax({
        url: 'ajax.php', //This is the current doc
        type: "POST",
        data: ({name: 145}),
        success: function(data){
            console.log(data);
            alert(data);
            //or if the data is JSON
            var jdata = jQuery.parseJSON(data);
        }
    });

#3

$(document).ready(function() {
    $("#raaagh").click(function() {
        $.ajax({
            url: 'ajax.php', //This is the current doc
            type: "POST",
            data: ({name: 145}),
            success: function(data) {
                console.log(data);
                $.ajax({
                    url:'ajax.php',
                    data: data,
                    dataType:'json',
                    success:function(data1) {
                        var y1=data1;
                        console.log(data1);
                    }
                });
            }
        });
    });
});

Use like this, first make a ajax call to get data, then your php function will return u the result which u wil get in data and pass that data to the new ajax call

像这样使用，首先进行ajax调用以获取数据，然后你的php函数将返回你将获得数据的结果并将该数据传递给新的ajax调用

#4

you have to pass values with the single quotes

你必须用单引号传递值

$(document).ready(function() {    
    $("#raaagh").click(function(){    
        $.ajax({
            url: 'ajax.php', //This is the current doc
            type: "POST",
            data: ({name: '145'}), //variables should be pass like this
            success: function(data){
                console.log(data);
                           }
        });  
        $.ajax({
    url:'ajax.php',
    data:"",
    dataType:'json',
    success:function(data1){
            var y1=data1;
            console.log(data1);
            }
        });

    });
});

try it it may work.......

尝试它可能会工作.......

#5

In your PhP file there's going to be a variable called $_REQUEST and it contains an array with all the data send from Javascript to PhP using AJAX.

在您的PhP文件中，将会有一个名为$ _REQUEST的变量，它包含一个数组，其中所有数据都使用AJAX从Javascript发送到PhP。

Try this: var_dump($_REQUEST); and check if you're receiving the values.

试试这个：var_dump（$ _ REQUEST）;并检查您是否收到了这些值。

#1