While looking at tons of examples of how to get a PHP variable sent to a JavaScript file, I still haven't had success getting it.
在查看大量如何将PHP变量发送到JavaScript文件的示例时,我仍然没有成功获得它。
My PHP file is:
我的PHP文件是:
$title = $json["title"];
echo json_encode($title);
And my JavaScript file app.js is:
我的JavaScript文件app.js是:
$.ajax({
url : 'index.php',
type : 'GET',
data : film,
dataType : 'json',
success : function (data) {
alert(data.title);
console.log(data.title);
},
})
I would like to know the right code to get the PHP $title variable to the ajax call in app.js.
我想知道正确的代码,以获得app.js中的ajax调用PHP $ title变量。
Thanks
谢谢
2 个解决方案
#1
2
For this example there are two files. One has the JQuery ajax
method. The other file is a PHP script that returns the requested information.
对于此示例,有两个文件。一个有JQuery ajax方法。另一个文件是一个返回所请求信息的PHP脚本。
show_title.html
show_title.html
<!-- JQuery library already loaded -->
<script>
$.ajax({
url : 'get_title.php', // requesting a PHP script
dataType : 'json',
success : function (data) { // data contains the PHP script output
alert(data.title);
console.log(data.title);
},
})
</script>
get_title.php
get_title.php
<?php
$json["title"] = 'a title';
echo json_encode($json);
?>
#2
2
If you'd want a .title
property on the response, then you should create an array then encode that instead. You got the other way around. Something like this:
如果您想在响应上使用.title属性,那么您应该创建一个数组,然后对其进行编码。你反过来了。像这样的东西:
PHP
PHP
<?php
$title = 'Yahoo!';
$json['title'] = $title;
echo json_encode($json);
#1
2
For this example there are two files. One has the JQuery ajax
method. The other file is a PHP script that returns the requested information.
对于此示例,有两个文件。一个有JQuery ajax方法。另一个文件是一个返回所请求信息的PHP脚本。
show_title.html
show_title.html
<!-- JQuery library already loaded -->
<script>
$.ajax({
url : 'get_title.php', // requesting a PHP script
dataType : 'json',
success : function (data) { // data contains the PHP script output
alert(data.title);
console.log(data.title);
},
})
</script>
get_title.php
get_title.php
<?php
$json["title"] = 'a title';
echo json_encode($json);
?>
#2
2
If you'd want a .title
property on the response, then you should create an array then encode that instead. You got the other way around. Something like this:
如果您想在响应上使用.title属性,那么您应该创建一个数组,然后对其进行编码。你反过来了。像这样的东西:
PHP
PHP
<?php
$title = 'Yahoo!';
$json['title'] = $title;
echo json_encode($json);