按周/月选择和求和值

I have a hash of dates and amounts like so:

我有一个日期和金额的哈希如下：

{
  "2014-01-30"=>200.1, 
  "2014-02-01"=>27.86, 
  "2014-02-02"=>55.72, 

  "2014-02-03"=>83.58, 
  "2014-02-04"=>83.58, 
  "2014-02-05"=>76.41, 
  "2014-02-06"=>187.85, 
  "2014-02-07"=>27.86, 
  "2014-02-08"=>27.86, 
  "2014-02-09"=>55.72, 

  "2014-02-10"=>269.34, 
  "2014-02-11"=>83.58, 
  "2014-02-12"=>159.99, 
  "2014-02-13"=>373.61, 
  "2014-02-14"=>264.26, 
  "2014-02-15"=>236.4, 

  "2014-02-17"=>215.71, 
  "2014-02-18"=>55.72, 
  "2014-02-19"=>132.13, 
  "2014-02-20"=>104.27, 
  "2014-02-21"=>83.58, 
  "2014-02-22"=>104.27, 
  "2014-02-23"=>159.99, 

  "2014-02-24"=>27.86, 
  "2014-02-25"=>172.24, 
  "2014-02-27"=>380.78, 
  "2014-02-28"=>336.82, 
  "2014-03-01"=>55.72, 
  "2014-03-02"=>83.58, 

  "2014-03-03"=>83.58, 
  "2014-03-04"=>224.02, 
  "2014-03-05"=>574.76, 
  "2014-03-06"=>853.14, 
  "2014-03-07"=>27.86, 
  "2014-03-09"=>83.58, 

  "2014-03-10"=>241.48, 
  "2014-03-11"=>208.54, 
  "2014-03-12"=>368.53, 
  "2014-03-13"=>941.42, 
  "2014-03-14"=>396.39, 
  "2014-03-15"=>320.71, 
  "2014-03-16"=>144.38, 

  "2014-03-17"=>215.71, 
  "2014-03-18"=>83.58, 
  "2014-03-19"=>227.44, 
  "2014-03-20"=>104.27, 
  "2014-03-21"=>111.32, 
  "2014-03-22"=>104.27, 
  "2014-03-23"=>238.86, 

  "2014-03-25"=>172.24
}

What I want to do is map those dates into "week" and "month" groups and sum the amount.

我想要做的是将这些日期映射到“周”和“月”组并总计金额。

So basically take the starting date and the ending date (in this case, 2014-01-30 and 2014-03-25) and then divide it in to calendar week periods and month periods and sum all the amounts of days in that range.

因此，基本上采取开始日期和结束日期（在本例中为2014-01-30和2014-03-25），然后将其划分为日历周期和月期，并将该范围内的所有天数相加。

In my example data above, you'll see it divided into actual weeks. And notice, a couple of those groupings only have 6 items as there wasn't an amount on one of the days.

在上面的示例数据中，您会看到它分为实际周数。请注意，其中一些分组只有6个项目，因为其中一天没有金额。

For the output, I'd want an array of each week/month range sum'd amount.

对于输出，我想要一个每周/每月范围总和数量的数组。

Output of the example data above would be: [283.68, 542.86, 1387.18, 855.67, 1057.00, 1846.94, 2621.45, 1085.45, 172.24]

上述示例数据的输出为：[283.68,542.86,1387.18,855.67,1057.00,1846.94,2621.45,1085.45,172.24]

FWIW, I'm suing Ruby 2 and Rails 4.

FWIW，我在起诉Ruby 2和Rails 4。

2 个解决方案

#1

# This for using outside Rails, remove if on Rails
require 'date'
gem 'activesupport'
require 'active_support/core_ext/date'
require 'active_support/core_ext/enumerable'

hash = {
  "2014-01-30"=>200.1, 
  "2014-02-01"=>27.86, 
  "2014-02-02"=>55.72, 

  [...]

  "2014-03-25"=>172.24
}

# group by week
p Hash[ hash.map { |h, v| [Date.parse(h), v] } ]
    .group_by { |h, v| h.cweek }
    .values
    .map { |v| v.sum { |v| v.last } }
    .map { |v| v.round(2) }

#=> [283.68, 542.86, 1387.18, 855.67, 1057.0, 1846.94, 2621.45, 1085.45, 172.24]

# group by month
p Hash[ hash.map { |h, v| [Date.parse(h), v] } ]
    .group_by { |h, v| h.month }
    .values
    .map { |v| v.sum { |v| v.last } }
    .map { |v| v.round(2) }

#=> [200.1, 3786.99, 5865.38]

After some refactoring:

经过一些重构：

# group by week
p hash
    .group_by { |h, _| Date.parse(h).cweek }
    .map { |_, v| v.sum { |v| v.last }.round(2) }

# group by month
p hash
    .group_by { |h, _| Date.parse(h).month }
    .map { |_, v| v.sum { |v| v.last }.round(2) }

If you are curious about why I used the underscore: http://po-ru.com/diary/rubys-magic-underscore/

如果您对我使用下划线的原因感到好奇：http：//po-ru.com/diary/rubys-magic-underscore/

#2

Try that :

试试看：

start_date = hash.min[0]
end_date = hash.max[0]
result = []
(start_date..end_date).each do |date|
  if date.wday == start_date.wday
    result << hash[date]
  else
    result[-1] += hash[date]
  end
end

Or just for the fun :

或者只是为了好玩：

(h.min[0]..h.max[0]).each {|d| (d.wday == h.min[0].wday && r << h[d])||(r[-1]+=h[d])}