对三个变量排序数组[重复]

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Swift - Sort array of objects with multiple criteria 8 answers

Swift - 使用多个条件排序对象数组8个答案

I have an array with playing cards. I would like to sort these on value, color and playability.

我有一个带扑克牌的阵列。我想根据价值,颜色和可玩性对它们进行排序。

I have 4 colors; 1, 2, 3, 4.

我有4种颜色; 1,2,3,4。

I have 3 playability options; 1, 2, 3.

我有3个可玩性选项; 1,2,3。

I have 5 values; 1, 2, 3, 4, 5.

我有5个值; 1,2,3,4,5。

I am able to sort the array on color and value. So if the color is the same, the array is sorted on value.

我能够在颜色和值上对数组进行排序。因此,如果颜色相同,则数组按值排序。

example color-value pairs:

示例颜色 - 值对:

1-2, 1-4, 1-5, 2-2, 3-1, 3-2, 3-5

Code is,

playerCards.sort {
       if $0.colorSorter == $1.colorSorter {
            return $0.value < $1.value
       }
        return $0.colorSorter < $1.colorSorter
    }

How do I add the third paramater to sort on playability additionally?

如何添加第三个参数以对可玩性进行排序?

What I would like to see (playability-color-value triplets):

我想看到的(可玩性 - 颜色值三元组):

1-1-2, 1-1-4, 1-2-2, 1-3-1, 2-1-5, 2-3-1, 2-3-2, 3-3-5

1: sort on playability 2: sort on color 3: sort on value.

1:对可玩性进行排序2:对颜色3进行排序:对值进行排序。

Thanks!

1 个解决方案

#1

Assuming this is your struct

假设这是你的结构

struct Card {
    let color:Int
    let value:Int
    let playability:Int
}

and this is your array

这是你的数组

let cards:[Card] = ...

You can sort cards by

您可以按卡排序

playability
color
value

writing

let sorted = cards.sorted { (left, right) -> Bool in
    guard left.playability == right.playability else { return left.playability < right.playability }
    guard left.color == right.color else { return left.color < right.color }
    return left.value < right.value
}

#1