Swift对包含字符串和数字的数组进行排序[重复]

This question already has an answer here:

这个问题在这里已有答案：

• Sorting array alphabetically with number 7 answers
• 按字母顺序排列数组7号答案

I have an array of strings,

我有一个字符串数组，

Array=[ "10", "1", "101", "NA", "100", "20", "210", "200", "NA", "7" ]

I would like to get the output sorted in ascending as,

我想将输出按升序排序为，

Sorted=[ "1", "7", "10", "20", "100", "101", "200", "210", "NA", "NA" ]

I tried using the sorted command but it does not work when it encounters more than 2 digits e.g.: 100, 101, 200 etc.

我尝试使用sorted命令，但遇到超过2位数时不起作用，例如：100,101,200等。

Array.sorted { $0? < $1? }

What would be the simple way to get this?

得到这个的简单方法是什么？

1 个解决方案

#1

You can use String method localizedStandardCompare

您可以使用String方法localizedStandardCompare

let array = [ "10", "1", "101", "NA", "100", "20", "210", "200", "NA", "7" ]
let sorted = array.sorted {$0.localizedStandardCompare($1) == .orderedAscending}

print(sorted) // ["1", "7", "10", "20", "100", "101", "200", "210", "NA", "NA"]