I have tried searching all possible matches of my problem and also have tried a couple of solutions but unfortunately none worked
My backend code:
我尝试过搜索我的问题的所有可能的匹配,并尝试了一些解决方案,但不幸的是,没有一个解决了我的后端代码:
Person p;
foreach(DataRow dr in dt.Rows)
{
p = new Person();
p.id = Convert.ToInt16(dr["Id"]);
p.name = dr["Name"].ToString();
p.phone = Convert.ToInt64(dr["Phone"]);
pList.Add(p);
}
string ans = JsonConvert.SerializeObject(pList, Formatting.Indented);
jQuery.ajax
jQuery.ajax
function ShowData() {
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: "Default.aspx/Data",
data: "{}",
dataType: "json",
success: function (data) {
alert(data.d);
var list = { "Person": +data };
for (i = 0; i < list.Person.length; i++) {
alert('Id: ' + list.Person[i].Id + '/nName: ' + list.Person[i].Name + '/nPhone: ' + list.Person[i].Phone);
console.log('Id: ' + list.Person[i].Id + '/nName: ' + list.Person[i].Name + '/nPhone: ' + list.Person[i].Phone);
}
console.log(list.Person.length);
},
error: function (result) {
alert("Error");
}
});
}
Alert output
报警输出
[
{
"id": 1,
"name": "Bhavik",
"phone": 9601109585
},
{
"id": 2,
"name": "Xyz",
"phone": 1234567890
},
{
"id": 3,
"name": "Abc",
"phone": 9876543210
}
]
console.log(list.Person.length);
returns undefined and hence does not enters the for loop.. So to work out with it.. and why is it necessary to specify contentType
while dataType
already exist.. Also can I use $.getJSON instead of $.ajax.
console.log(list.Person.length);返回未定义的,因此不进入for循环。所以,为了解决这个问题。为什么需要指定contentType而数据类型已经存在。我也可以用$。getJSON代替美元. ajax。
2 个解决方案
#1
3
You should change your code to be var list = {"Person": data.d}; to reflect what you're alerting.
您应该将您的代码更改为var list ={“Person”:data.d};以反映你的警觉。
function ShowData() {
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: "Default.aspx/Data",
data: "{}",
dataType: "json",
success: function (data) {
alert(data.d);
var list = { "Person": +data.d };
for (i = 0; i < list.Person.length; i++) {
alert('Id: ' + list.Person[i].Id + '/nName: ' + list.Person[i].Name + '/nPhone: ' + list.Person[i].Phone);
console.log('Id: ' + list.Person[i].Id + '/nName: ' + list.Person[i].Name + '/nPhone: ' + list.Person[i].Phone);
}
console.log(list.Person.length);
},
error: function (result) {
alert("Error");
}
});
}
#2
0
Also this should be a GET request not a post, then you would be able to use $.getJSON.
这也应该是GET请求而不是post,这样你就可以使用$. getjson。
#1
3
You should change your code to be var list = {"Person": data.d}; to reflect what you're alerting.
您应该将您的代码更改为var list ={“Person”:data.d};以反映你的警觉。
function ShowData() {
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: "Default.aspx/Data",
data: "{}",
dataType: "json",
success: function (data) {
alert(data.d);
var list = { "Person": +data.d };
for (i = 0; i < list.Person.length; i++) {
alert('Id: ' + list.Person[i].Id + '/nName: ' + list.Person[i].Name + '/nPhone: ' + list.Person[i].Phone);
console.log('Id: ' + list.Person[i].Id + '/nName: ' + list.Person[i].Name + '/nPhone: ' + list.Person[i].Phone);
}
console.log(list.Person.length);
},
error: function (result) {
alert("Error");
}
});
}
#2
0
Also this should be a GET request not a post, then you would be able to use $.getJSON.
这也应该是GET请求而不是post,这样你就可以使用$. getjson。