SQL从多个表中选择不同的值。

So here's my setup I have 2 tables Old and New with the following (simplified) schemas

这是我的设置，我有2个表，旧的和新的，有下面的(简化的)模式。

Old
[ManName]
[ManNumber]

New
[Manager_Name]
[Manager_Number]

I'm looking to craft a SQL query that returns the following but in 4 columns in 1 query as opposed to 2 queries with 2 columns each

我希望编写一个SQL查询，它返回以下内容，但在1个查询中的4个列中，与2个列的2个查询相反。

select distinct manname, mannumber from OLD 
select distinct Manager_Name, Manager_Number from NEW

So my ideal Result Set would have 4 columns:

所以理想的结果集是4列

ManName ManNumber Manager_Name Manager Number

Thanks!

谢谢!

2 个解决方案

#1

have you tried a JOIN statement:

你是否尝试过加入声明:

select distinct * 
from old a join new b on a.ManName = b. Manager_Name and a. ManNumber = b. Manager_Number

#2

Using pretty much any RDBMS except MySQL, you can do it with CTEs and ROW_NUMBER();

除了MySQL之外，使用几乎任何RDBMS，都可以使用CTEs和ROW_NUMBER();

WITH cteOld AS (
  SELECT DISTINCT ManName, ManNumber, 
         ROW_NUMBER() OVER (ORDER BY ManNumber) rn FROM Old
), cteNew AS (
  SELECT DISTINCT Manager_Name, Manager_Number,
         ROW_NUMBER() OVER (ORDER BY Manager_Number) rn FROM New
)
SELECT ManName, ManNumber, Manager_Name, Manager_Number 
FROM cteOld
FULL OUTER JOIN cteNew
  ON cteOld.rn=cteNew.rn

An SQLfiddle to test with.

一个用来测试的SQLfiddle。

Another, easier, way to just get all of them is to simply use a UNION;

另一个更简单的方法就是简单地使用一个联合;

SELECT ManName, ManNumber, 0 isNew FROM Old
UNION 
SELECT Manager_Name, Manager_Number, 1 FROM New

Another SQLfiddle.

另一个SQLfiddle。

#1