Sql从另一个查询中选择多个值

I have three tables in php-mysql products,product_fact,fact schema is like this

我在php-mysql产品中有三个表，product_fact，fact schema就是这样的

products

制品

 id , name (1000 records)

Eg-

例如-

id     |    name
-------+--------
1125   | key chain
1135   | bikes
1145   | cars

id = has different id numbers of the products every product has a unique id,

id =具有不同的产品ID号，每个产品都有唯一的ID，

name = name of products

name =产品名称

product_fact

product_fact

product_id, fact_id

product_id = this is the same id that is in products table

product_id =这与products表中的id相同

fact_id = this is fact id every products have some facts, many of the products has more than one fact.

fact_id =这是事实id每个产品都有一些事实，很多产品都有不止一个事实。

Eg-

例如-

product_id  |  fact_id
------------+----------
1125        |      5
1125        |      7
1125        |      6
1135        |      8
1145        |      9
1145        |      2

fact

事实

id , name

id = this is fact_id same as in table product_fact

id = this is fact_id与表product_fact中的相同

name = this is the name of fact.

name =这是事实的名称。

Eg-

例如-

id      |    name
--------+---------
 2      |   black
 8      |   free
 5      |   sold
 6      |   coming soon
 9      |   new

Now i want to select particular fact name related to the product, but when i execute this query -->

现在我想选择与产品相关的特定事实名称，但是当我执行此查询时 - >

SELECT name
FROM fact
Where id = (SELECT fact_id
FROM product_fact
Where product_id='1125');

It says Subquery returns more than 1 row

它说Subquery返回超过1行

But when i run this query -->

但是当我运行这个查询 - >

SELECT name
FROM fact
Where id = (SELECT fact_id
FROM product_fact
Where product_id='1135');

It gives me correct output : free

它给了我正确的输出：免费

What should i do now it should display fact name's for other products any help, what else should i have to include in my query.. any help

我现在应该怎么做它应该显示其他产品的事实名称任何帮助，我还应该包括在我的查询中..还有什么帮助

1 个解决方案

#1

to be more safe with subquery, use IN instead of =

使用子查询更安全，使用IN而不是=

SELECT name 
FROM   fact 
Where id IN (SELECT fact_id 
             FROM   product_fact 
             WHERE  product_id='1125');

or using JOIN

或使用JOIN

SELECT  DISTINCT a.name
FROM    fact a
        INNER JOIN product_fact b
            ON a.ID = b.fact_ID
WHERE   b.product_ID = '1125'

#1