Django模板访问嵌套数据

This seems silly, but I don't understand how Django Templates access nested data in Contexts. I can access the values of dictionaries nested in the context data structure with the . notation -- {{ aDictionary.i_am_a_key }} works fine. But if I try to iterate over a list of keys and get their value from that same dictionary, I get nothing. So

这看起来很傻，但我不明白Django Templates如何在Contexts中访问嵌套数据。我可以访问嵌套在上下文数据结构中的字典值。符号 - {{aDictionary.i_am_a_key}}运行正常。但是，如果我尝试迭代一个键列表并从同一个字典中获取它们的值，我什么也得不到。所以

{% for key in keys_list %}{{ aDictionary.key }}{% endfor}}

{％for key in keys_list％} {{aDictionary.key}} {％endfor}}

just generates blanks.

只是生成空白。

What am I missing here? Does Django not support key access to context dictionaries on the fly? Do I need to write a custom tag to do this?

我在这里想念的是什么？ Django不支持动态上下文字典的密钥访问吗？我是否需要编写自定义标记才能执行此操作？

EDIT

编辑

My examples assume these data structures:

我的例子假设这些数据结构：

aDictionary = {'i_am_a_key': 'all good', 'i_am_another_key': 'okay'}
keys_list = ['i_am_a_key', 'i_am_another_key']

3 个解决方案

#1

This is a fundamental limitation of the Django templating language.

这是Django模板语言的基本限制。

Three solutions:

三种解决方案

Use {% for key,value in foo.items %} to get key and value.
使用{％for key，value in foo.items％}来获取键和值。
Use Jinja2 -- an almost Django-like templating system.
使用Jinja2 - 一个几乎类似Django的模板系统。
User the expr djangosnippet to do the access math.
用户使用expr djangosnippet进行访问数学运算。

#2

This is a different approach, but based on what you want to accomplish this is the angle I'd take.

这是一种不同的方法，但基于你想要实现的目标，这就是我所采取的角度。

If you want to keep a subset of some dictionary and you want to iterate around it's values in some ordered fashion, I'd copy the element you're interested in into a SortedDict (django/utils/datastructures.py).

如果你想保留一些字典的子集，并且想要以某种有序的方式迭代它的值，我会将你感兴趣的元素复制到SortedDict（django / utils / datastructures.py）中。

In my mind, stuff like this should live in the view (all of this is untested):

在我看来，像这样的东西应该存在于视图中（所有这些都是未经测试的）：

sorted_dict = SortedDict()
for key in orig_dict:
    if interested(key):
        sorted_dict[key] = orig_dict[val]

and the templates should just be very dumb:

模板应该是非常愚蠢的：

{% for key, val in sorted_dict.items %}{{ val }}{% endfor}}

#3

It's not the same question, but the answer is similar to #844746.

这不是同一个问题，但答案类似于＃844746。

You end up with a filter which you can do...

你最终得到了一个过滤器，你可以做...

{% load getattribute %}
{% for key in keys_list %}
    {{ aDictionary|attr:key }}
{% endfor %}

#1