leetcode不会-delete-node-in-a-linked-list:删除链表中的节点

时间:2024-07-19 21:07:02
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文件名称:leetcode不会-delete-node-in-a-linked-list:删除链表中的节点

文件大小:1KB

文件格式:ZIP

更新时间:2024-07-19 21:07:02

系统开源

leetcode 不会删除链表中的节点 编写一个函数来删除单向链表中的节点(尾部除外),只允许访问该节点。 给定链表——head = [4,5,1,9]。 Example 1: Input: head = [4,5,1,9], node = 5 Output: [4,1,9] Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function. Example 2: Input: head = [4,5,1,9], node = 1 Output: [4,5,9] Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function. 笔记: 链表将至少有两个元素。 所有节点的值都将是唯一的。 给定的节点不会是尾部,它将始终


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delete-node-in-a-linked-list-master
----README.md(1KB)

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