I just used the following grep command:
我刚刚使用了以下grep命令：
grep -ri '^(<topicref |<mapref).*( )(dest=")'
to match the following:
匹配以下内容：
<topicref version="1" dest="susu"/>
<mapref id="" dest="summat"/>
all topicref and mapref that have a dest attribute.
具有dest属性的所有topicref和mapref。
However, it didnt work although regexpal accepts the regex. How do I have to change this to work with grep?
但是，虽然regexpal接受正则表达式，但它没有用。如何将其更改为与grep一起使用？
1 个解决方案
#1
1
If you would like to use parentheses and alternation without using extended regular expressions, you can escape them with the backslash to enable this functionality.
如果要在不使用扩展正则表达式的情况下使用括号和替换，可以使用反斜杠对其进行转义以启用此功能。
grep -ir '^\(<topicref \|<mapref\).*\( \)\(dest="\)' .
Or, you can use -E option, and then you do not have to escape brackets:
或者，您可以使用-E选项，然后您不必转义括号：
grep -iEr '^(<topicref |<mapref).*( )(dest=")' .
Mind the . at the end stands for the current directory, and together with r recursive option, this will fetch you all the matches in the directory files.
记住。最后代表当前目录，与r recursive选项一起，这将获取目录文件中的所有匹配项。
#1
1
If you would like to use parentheses and alternation without using extended regular expressions, you can escape them with the backslash to enable this functionality.
如果要在不使用扩展正则表达式的情况下使用括号和替换，可以使用反斜杠对其进行转义以启用此功能。
grep -ir '^\(<topicref \|<mapref\).*\( \)\(dest="\)' .
Or, you can use -E option, and then you do not have to escape brackets:
或者，您可以使用-E选项，然后您不必转义括号：
grep -iEr '^(<topicref |<mapref).*( )(dest=")' .
Mind the . at the end stands for the current directory, and together with r recursive option, this will fetch you all the matches in the directory files.
记住。最后代表当前目录，与r recursive选项一起，这将获取目录文件中的所有匹配项。