I'm having hard time trying to figure out regular expression that will extract 4 digits long number after certain word as full match.
我很难找出正则表达式，它会在某个单词作为完全匹配后提取4位数的长数字。
Here is the text:
这是文字：
FV 7017 FOR SOMETHING 1076,33 USD.
and here is my regular expression to extract the 4 digits number:
这是我的正则表达式提取4位数字：
/FV (\d{4,})/
That will result in:
这将导致：
Full match = `FV 7017`
Group 1 match = `7017`
Is it possible to exclude that "FV" word using regex to have that result as full match?
是否可以使用正则表达式排除“FV”单词以使结果完全匹配？
2 个解决方案
#1
0
4 steps faster than a positive lookbehind, is to use \K to restart the fullstring match.
比正面lookbehind快4步，就是使用\ K来重启全字符串匹配。
/FV \K\d{4}/
模式演示
PHP Implementation:
PHP实现：
$string='FV 7017 FOR SOMETHING 1076,33 USD.';
echo preg_match('/FV \K\d{4}/',$string,$out)?$out[0]:'fail';
// output: 7017
#2
#1
0
4 steps faster than a positive lookbehind, is to use \K to restart the fullstring match.
比正面lookbehind快4步，就是使用\ K来重启全字符串匹配。
/FV \K\d{4}/
模式演示
PHP Implementation:
PHP实现：
$string='FV 7017 FOR SOMETHING 1076,33 USD.';
echo preg_match('/FV \K\d{4}/',$string,$out)?$out[0]:'fail';
// output: 7017