I want to find a word in a string i.e,whether a word is present in particular string or not.
我想在一个字符串中找到一个单词,即一个单词是否存在于特定的字符串中。
String 1 Has:
字符串1有:
Case Number
1
SKU Barcode
案例编号1 SKU条形码
String 2 Has:
字符串2有:
Case Number
案件编号
I want to find whether Case Number is present in string 1 or not .
我想查找字符串1中是否存在案例编号。
if ([string1 rangeOfString:string2].location !=NSNotFound) {
NSLog(@"matched");}
else
{ NSLog(@"not matched");}
but here i am getting not matched ...why ..And then what is the difference of using .location and .length Output:
但在这里我得不到匹配...为什么..然后使用.location和.length输出的区别是什么:
2017-05-04 11:38:33.128495 Link[26540:17390387] String 1: Case Number
1
SKU Barcode
2017-05-04 11:38:33.128495链接[26540:17390387]字符串1:案例编号1 SKU条形码
2017-05-04 11:38:33.129301 Link[26540:17390387] String 2: Case Number
2017-05-04 11:38:33.129301链接[26540:17390387]字符串2:案例编号
Thanks in advance!
提前致谢!
3 个解决方案
#1
1
NSString *string1 = @"Case Number \n 1 \n SKU Barcode";
NSString *string2 = @"Case Number";
if ([string1 rangeOfString:string2].location !=NSNotFound) {
NSLog(@"matched");}
else
{ NSLog(@"not matched");}
}
It works for me.
这个对我有用。
#2
0
If you are supporting iOS 8.0 onwards, you can use containsString
:
如果您支持iOS 8.0以上,则可以使用containsString:
if ([string1 containsString:string2])
NSLog(@"matched");
else
NSLog(@"not matched");
If this doesn't work, then there's something wrong with one or both of your strings (e.g. additional space or control characters at the end).
如果这不起作用,那么你的一个或两个字符串就会出现问题(例如最后的附加空格或控制字符)。
#3
0
Your string2 contains characters other than @"Case Number". Test by inserting the following lines into your code.
您的string2包含@“案例编号”以外的字符。通过在代码中插入以下行进行测试。
if([string2 isEqualToString:@"Case Number"]) NSLog(@"String 2 is OK");
else NSLog(@"String 2 is bad!");
#1
1
NSString *string1 = @"Case Number \n 1 \n SKU Barcode";
NSString *string2 = @"Case Number";
if ([string1 rangeOfString:string2].location !=NSNotFound) {
NSLog(@"matched");}
else
{ NSLog(@"not matched");}
}
It works for me.
这个对我有用。
#2
0
If you are supporting iOS 8.0 onwards, you can use containsString
:
如果您支持iOS 8.0以上,则可以使用containsString:
if ([string1 containsString:string2])
NSLog(@"matched");
else
NSLog(@"not matched");
If this doesn't work, then there's something wrong with one or both of your strings (e.g. additional space or control characters at the end).
如果这不起作用,那么你的一个或两个字符串就会出现问题(例如最后的附加空格或控制字符)。
#3
0
Your string2 contains characters other than @"Case Number". Test by inserting the following lines into your code.
您的string2包含@“案例编号”以外的字符。通过在代码中插入以下行进行测试。
if([string2 isEqualToString:@"Case Number"]) NSLog(@"String 2 is OK");
else NSLog(@"String 2 is bad!");