I hold decimals in a database using DECIMAL(10,5)
我使用DECIMAL(10,5)在数据库中保存小数
I would like to format these numbers according to a few rules:
我想根据一些规则格式化这些数字:
- A zero decimal should display as 0
- Show a long decimal (no trailing zero's) with all of it's numbers
- When possible, I would like to only show up to 2 decimal places (when there are trailing zeros)
零小数应显示为0
显示一个长十进制(没有尾随零)的所有数字
如果可能的话,我想只显示2位小数(当有尾随零时)
Here are some examples:
这里有些例子:
- The left side corresponds to how the number is stored in database.
- The right number is how I would like to display the number in my application.
左侧对应于数字在数据库中的存储方式。
正确的数字是我想在我的应用程序中显示数字的方式。
0.00000 => 0
0.51231 => 0.51231
0.12000 => 0.12
0.40000 => 0.40
0.67800 => 0.678
12.10000 => 12.10
5 个解决方案
#1
2
This will work for you:
这对你有用:
function format($x){
if(!(int)substr_replace($x, '', $dpos = strpos($x, '.'), 1))
return 0;
else
return str_pad((rtrim($x, '0')), $dpos + 3, '0');
}
#2
1
Well here's one way (I haven't tested it yet so there may be minor errors):
那么这是一种方式(我还没有测试它,所以可能会有一些小错误):
$pattern = '/([0-9]+)\\.{0,1}([0-9]*?)0*$/';
$subject = 12.10000;
$matches = array();
$result = preg_match ($pattern, $subject, $matches);
$number = $matches[1];
if ($matches[2] != 0) {
$number .= '.'.$matches[2];
if ($matches[2] < 10) {
$number .= '0';
}
}
echo $number;
And here's another way (probably a little faster):
这是另一种方式(可能更快一点):
$x = 1.000;
$result = (int)$x;
$trimmed = rtrim($x, 0);
if ($trimmed[strlen($trimmed) - 1] != '.') {
if ($trimmed[strlen($trimmed) - 2] == '.') {
$result = $trimmed.'0';
} else {
$result = $trimmed;
}
}
echo $result;
#3
0
I would utilize the number_format function in php to actually do the formatting after you determine the amount of decimal places to the number has.
在确定数字的小数位数后,我会利用php中的number_format函数实际进行格式化。
Source: http://php.net/manual/en/function.number-format.php
Example Usage:
$number = 1234.56;
// english notation (default)
$english_format_number = number_format($number);
// 1,235
// French notation
$nombre_format_francais = number_format($number, 2, ',', ' ');
// 1 234,56
$number = 1234.5678;
// english notation without thousands separator
$english_format_number = number_format($number, 2, '.', '');
// 1234.57
#4
0
I haven't used it myself, but theres the NumberFormatter class: http://php.net/manual/class.numberformatter.php as part of the Internationalization Functions for this stuff. Using that is a little more involved i think though.
我自己没有使用它,但是还有NumberFormatter类:http://php.net/manual/class.numberformatter.php作为这个东西的国际化功能的一部分。尽管如此,使用它还是更复杂一些。
#5
0
I know this is an old question, but the following quick function I wrote for my own project might help someone looking for this.
我知道这是一个老问题,但我为自己的项目编写的以下快速功能可能会帮助有人找到这个。
function number_format_least_dp($number, $decimal_point = '.', $thousand_seperator = ','){
if (floatval($number) == (int)$number){
$number = number_format($number, 0, $decimal_point, $thousand_seperator);
} else {
$number = rtrim($number, '.0');
$number = number_format($number, strlen(substr(strrchr($number, '.'), 1)), $decimal_point, $thousand_seperator);
}
return $number;
}
#1
2
This will work for you:
这对你有用:
function format($x){
if(!(int)substr_replace($x, '', $dpos = strpos($x, '.'), 1))
return 0;
else
return str_pad((rtrim($x, '0')), $dpos + 3, '0');
}
#2
1
Well here's one way (I haven't tested it yet so there may be minor errors):
那么这是一种方式(我还没有测试它,所以可能会有一些小错误):
$pattern = '/([0-9]+)\\.{0,1}([0-9]*?)0*$/';
$subject = 12.10000;
$matches = array();
$result = preg_match ($pattern, $subject, $matches);
$number = $matches[1];
if ($matches[2] != 0) {
$number .= '.'.$matches[2];
if ($matches[2] < 10) {
$number .= '0';
}
}
echo $number;
And here's another way (probably a little faster):
这是另一种方式(可能更快一点):
$x = 1.000;
$result = (int)$x;
$trimmed = rtrim($x, 0);
if ($trimmed[strlen($trimmed) - 1] != '.') {
if ($trimmed[strlen($trimmed) - 2] == '.') {
$result = $trimmed.'0';
} else {
$result = $trimmed;
}
}
echo $result;
#3
0
I would utilize the number_format function in php to actually do the formatting after you determine the amount of decimal places to the number has.
在确定数字的小数位数后,我会利用php中的number_format函数实际进行格式化。
Source: http://php.net/manual/en/function.number-format.php
Example Usage:
$number = 1234.56;
// english notation (default)
$english_format_number = number_format($number);
// 1,235
// French notation
$nombre_format_francais = number_format($number, 2, ',', ' ');
// 1 234,56
$number = 1234.5678;
// english notation without thousands separator
$english_format_number = number_format($number, 2, '.', '');
// 1234.57
#4
0
I haven't used it myself, but theres the NumberFormatter class: http://php.net/manual/class.numberformatter.php as part of the Internationalization Functions for this stuff. Using that is a little more involved i think though.
我自己没有使用它,但是还有NumberFormatter类:http://php.net/manual/class.numberformatter.php作为这个东西的国际化功能的一部分。尽管如此,使用它还是更复杂一些。
#5
0
I know this is an old question, but the following quick function I wrote for my own project might help someone looking for this.
我知道这是一个老问题,但我为自己的项目编写的以下快速功能可能会帮助有人找到这个。
function number_format_least_dp($number, $decimal_point = '.', $thousand_seperator = ','){
if (floatval($number) == (int)$number){
$number = number_format($number, 0, $decimal_point, $thousand_seperator);
} else {
$number = rtrim($number, '.0');
$number = number_format($number, strlen(substr(strrchr($number, '.'), 1)), $decimal_point, $thousand_seperator);
}
return $number;
}