I have this code that works fine:
我有这个代码工作正常：
time1=23245321;
ratio=0.9761;
time1=int(time1*ratio);
but I get it not to work when I transform the 'ratio' variable to a parameter passed to the script with the -v option - time1 results to be equal to 0 (zero).
但是当我将'ratio'变量转换为使用-v选项传递给脚本的参数时，我认为它不起作用 - time1结果等于0（零）。
awk -f script.awk -v ratio=0.9761
awk -f script.awk -v ratio = 0.9761
It seems ratio is no longer treated as a float. How can I solve this problem?
似乎比率不再被视为浮动。我怎么解决这个问题？
2 个解决方案
#1
1
This works fine on my machine:
这在我的机器上工作正常：
awk -v ratio=0.9761 '{
time1=23245321;
time1=int(time1*ratio);
print ratio,time1}' <(echo "Hello world!")
It returns:
它返回：
0.9761 22689757
#2
1
It was just a 'locale' issue: I should have called the script using
这只是一个“语言环境”问题：我应该使用调用脚本
awk -f script.awk -v ratio=0,9761
because the comma is the decimal separator on my laptop
因为逗号是我笔记本电脑上的小数分隔符
#1
1
This works fine on my machine:
这在我的机器上工作正常：
awk -v ratio=0.9761 '{
time1=23245321;
time1=int(time1*ratio);
print ratio,time1}' <(echo "Hello world!")
It returns:
它返回：
0.9761 22689757
#2
1
It was just a 'locale' issue: I should have called the script using
这只是一个“语言环境”问题：我应该使用调用脚本
awk -f script.awk -v ratio=0,9761
because the comma is the decimal separator on my laptop
因为逗号是我笔记本电脑上的小数分隔符