wondered if you could help me please? I have node in xml that is as followed
想知道你能帮我吗?我在xml中有节点,如下所示
$LOG: 08880xbpnd $
fhdsafidsfsd
df
sd
fsd
f
sd
fsd
I was wondering is there anyway to make all the text go on to one line so that it then can be passsed through to a javascript function? so it would turn out like this
我想知道是否有任何方法让所有文本继续到一行,以便它可以传递到一个JavaScript函数?所以它会变成这样
$LOG: 08880xbpnd $fhdsafidsfsddfsdfsdfsdfsd
2 个解决方案
#1
13
Unfortunately, the normalize-space()
function (used in the answer of andynormancx) does more than deleting newlines.
不幸的是,normalize-space()函数(在andynormancx的答案中使用)不仅仅是删除换行符。
It deletes all leading and trailing whitespace and it replaces any group of inner contigious whitespace with a single space character.
它删除所有前导和尾随空格,并用一个空格字符替换任何一组内部可拥有的空格。
In many cases we want to deleteonly one type of a white-space character (as in the current case -- new lines (CR+LF is automatically normalized on reading by the XML parser to just LF).
在许多情况下,我们只想删除一种类型的空白字符(如在当前情况下 - 新行(CR + LF在XML解析器读取时自动规范化为LF)。
The correct and safe way to do so is by using the standard XPath translate()
function:
正确和安全的方法是使用标准的XPath translate()函数:
translate(., '
', '')
returns a string obtained from the string-value of the current node in which any newline character is deleted.
返回从当前节点的字符串值获取的字符串,其中删除了任何换行符。
Here is an example:
这是一个例子:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="text()">
<xsl:value-of
select="translate(.,'
','')"/>
</xsl:template>
</xsl:stylesheet>
When the above transformation is applied on this source XML document:
在此源XML文档上应用上述转换时:
<t>
$LOG: 08880xbpnd $
"embedded blanks must stay"
df
sd
fsd
f
sd
fsd
</t>
The result is on one line only, as required, and all embedded spaces are left intact:
结果仅在一行上,根据需要,所有嵌入的空格保持不变:
<t>$LOG: 08880xbpnd $"embedded blanks must stay"dfsdfsdfsdfsd</t>
#1
13
Unfortunately, the normalize-space()
function (used in the answer of andynormancx) does more than deleting newlines.
不幸的是,normalize-space()函数(在andynormancx的答案中使用)不仅仅是删除换行符。
It deletes all leading and trailing whitespace and it replaces any group of inner contigious whitespace with a single space character.
它删除所有前导和尾随空格,并用一个空格字符替换任何一组内部可拥有的空格。
In many cases we want to deleteonly one type of a white-space character (as in the current case -- new lines (CR+LF is automatically normalized on reading by the XML parser to just LF).
在许多情况下,我们只想删除一种类型的空白字符(如在当前情况下 - 新行(CR + LF在XML解析器读取时自动规范化为LF)。
The correct and safe way to do so is by using the standard XPath translate()
function:
正确和安全的方法是使用标准的XPath translate()函数:
translate(., '
', '')
returns a string obtained from the string-value of the current node in which any newline character is deleted.
返回从当前节点的字符串值获取的字符串,其中删除了任何换行符。
Here is an example:
这是一个例子:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="text()">
<xsl:value-of
select="translate(.,'
','')"/>
</xsl:template>
</xsl:stylesheet>
When the above transformation is applied on this source XML document:
在此源XML文档上应用上述转换时:
<t>
$LOG: 08880xbpnd $
"embedded blanks must stay"
df
sd
fsd
f
sd
fsd
</t>
The result is on one line only, as required, and all embedded spaces are left intact:
结果仅在一行上,根据需要,所有嵌入的空格保持不变:
<t>$LOG: 08880xbpnd $"embedded blanks must stay"dfsdfsdfsdfsd</t>