ajax在php页面上获得一个值的结果

This will return only one row how to simply pass that row to ajax call. below code passing data , but when i print it in loop it print unlimited times.

这将只返回一行如何简单地将该行传递给ajax调用。下面的代码传递数据,但当我在循环中打印它时,它打印无限次。

AJAX::

$.ajax({
  type: "POST",
  url: 'userLoginCheckforRetrieve.php',
  data: {
  },
   success:function(data)   { 
   alert('outside loop is '+data);
 for(var i=0; i < data.length ; i++){
    alert('loop date is '+data[i].name);
    }
}
});

PHP ::

$sel_query= "SELECT image_name FROM save_designs WHERE user_name='{$username}'";
    $sel_result = mysql_query($sel_query);

    $data = array();
    while($item = mysql_fetch_object($sel_result))
        {
            $data[] = array(
                'name' => $item->image_name                
            );
        }
    echo json_encode($data);

2 个解决方案

#1

Use JSON.parse to parse a string as JSON. Try this:

使用JSON.parse将字符串解析为JSON。试试这个:

$.ajax({
  type: "POST",
 url: 'userLoginCheckforRetrieve.php',
 data: {}, //Pass data here
 success:function(data)   { 
     var obj = JSON.parse(data); // parse a string as JSON
    alert('outside loop is '+data);
    for(var i=0; i < obj.length ; i++){
      alert('loop date is '+obj[i].name);
    }
  }
});

#2

You should add a JSON parser to convert it...

你应该添加一个JSON解析器来转换它...

$.ajax({
       type: "POST",
       url: 'userLoginCheckforRetrieve.php',
       data: {},
       success:function(data)   { 
         data = $.parseJSON(data);
         for(var i=0; i < data.length; i++){
         alert('loop date is '+data[i].name);
       }}
});

The json returned is a string so by parsing it you will create an object that contain all the json string elements and their values.

返回的json是一个字符串,因此通过解析它,您将创建一个包含所有json字符串元素及其值的对象。

Note: make sure you php files has no warnings that are printed and that the returned page is a clean JSON string => { .... }

注意:确保php文件没有打印的警告,并且返回的页面是干净的JSON字符串=> {....}

have Fun!

#1