I've following small code snippet to display today's date and value of one variable but I'm getting the blank white page in result. Why so?
我已经按照小代码片段来显示今天的日期和一个变量的值,但我得到的结果是空白页。为什么这样?
My code is as below:
我的代码如下:
<?php
$form_data['trans_date'] = '12-11-2014';// Date format is MM-DD-YYYY i.e. 11th December 2014
$newTransDate = DateTime::createFromFormat('!m-d-Y', $form_data['trans_date']);
$today_date = new DateTime('today');
echo "Today Date ".$today_date; die;//Here I want to print today's date
$form_data['trans_date'] = '12-11-2014';
$newTransDate = DateTime::createFromFormat('!m-d-Y', $form_data['trans_date']);
$today_date = new DateTime('today');
echo "Today Date ".$newTransDate."<br>"; die;//Here I wan tot print today's date
echo "New Trans Date ".$newTransDate; die;//Here I wan tot print value of var $newTransDate
?>
Thanks in advance.
提前致谢。
1 个解决方案
#1
0
When you are using PHP's DateTime, while outputting you need to define the output format.
当您使用PHP的DateTime时,在输出时您需要定义输出格式。
// Create a new DateTime object
$now = new DateTime();
// Output
echo $now->format('Y-m-d H:i:s');
#1
0
When you are using PHP's DateTime, while outputting you need to define the output format.
当您使用PHP的DateTime时,在输出时您需要定义输出格式。
// Create a new DateTime object
$now = new DateTime();
// Output
echo $now->format('Y-m-d H:i:s');