Sorry this is a very newbie question, but I just can't seem to get it to work.
对不起，这是一个非常新手的问题，但我似乎无法让它工作。
in my bash script, I have
在我的bash脚本中，我有
python=/path/to/python
script=$1
exec $python $script "$@"
How would I pass an argument, say -O to the python interpreter? I have tried:
我如何传递一个参数，比如说-O到python解释器？我努力了：
exec $python -O $script "$@"
exec $ python -O $ script“$ @”
And have tried changing python variable to "/path/to/python -O", as well as passing -O to the script, but every time i do any of these three, I get import errors for modules that succeed when I remove the -O.
并尝试将python变量更改为“/ path / to / python -O”，以及将-O传递给脚本，但每次我执行这三个中的任何一个时，我会在删除时取得成功的模块导入错误-O。
So my question is how to tell the python interpreter to run with -O argument from a bash script?
所以我的问题是如何告诉python解释器使用bash脚本中的-O参数运行？
Thanks.
谢谢。
1 个解决方案
#1
1
You should shift your positional parameters to the left by 1 to exclude your script which is in the first arguments from being included to the arguments for python.
您应该将位置参数向左移动1，以排除第一个参数中的脚本被包含到python的参数中。
#!/bin/sh
python=/path/to/python
script=$1; shift
exec "$python" -O "$script" "$@"
Then run the script as bash script.sh your_python_script arg1 arg2 ... or sh script.sh your_python_script arg1 arg2 ....
然后将脚本运行为bash script.sh your_python_script arg1 arg2 ...或者sh script.sh your_python_script arg1 arg2 ....
#1
1
You should shift your positional parameters to the left by 1 to exclude your script which is in the first arguments from being included to the arguments for python.
您应该将位置参数向左移动1，以排除第一个参数中的脚本被包含到python的参数中。
#!/bin/sh
python=/path/to/python
script=$1; shift
exec "$python" -O "$script" "$@"
Then run the script as bash script.sh your_python_script arg1 arg2 ... or sh script.sh your_python_script arg1 arg2 ....
然后将脚本运行为bash script.sh your_python_script arg1 arg2 ...或者sh script.sh your_python_script arg1 arg2 ....