I have this code:
我有这段代码:
...
msgdict = {'datafile': datafile, 'mapper': mapper, 'reducer':reducer}
msg = cPickle.dumps(msgdict)
print msg
The print msg I get this:
打印msg我得到这个:
(dp1
S'mapper'
p2
(S's3n://myFolder/mapper.py'
p3
tp4
sS'datafile'
p5
(S's3n://myFolder/test.txt'
p6
tp7
sS'reducer'
p8
(S's3n://myFolder/reducer.py'
p9
tp10
s.
Then Im trying to get my content:
然后我试图得到我的内容:
for i in range(count):
m = q[0].read()
# this print returns a object Message
print m
# m.get_body()) returns the same of print msg above
msg = cPickle.loads(m.get_body())
But Im having this errror:
但是我有这个错误:
msg = cPickle.loads(m.get_body())
TypeError: must be string, not unicode
Someone knows how to solve this error?
有人知道如何解决这个错误吗?
1 个解决方案
#1
7
Try to replace that line with the following:
试着用以下方法替换这一行:
msg = cPickle.loads(str(m.get_body()))
By casting str()
to m.get_body()
, it makes sure that if the string is unicode, it converts it to a string.
通过将str()转换为m.get_body(),它确保如果字符串是unicode,它将它转换为字符串。
#1
7
Try to replace that line with the following:
试着用以下方法替换这一行:
msg = cPickle.loads(str(m.get_body()))
By casting str()
to m.get_body()
, it makes sure that if the string is unicode, it converts it to a string.
通过将str()转换为m.get_body(),它确保如果字符串是unicode,它将它转换为字符串。