如何解析包含许多整数的字符串

I'm trying to read some int from a xml document:

我正在尝试从xml文档中读取一些int:

<aaa>
    <agent>
       <name>Agent 1</name>
       <position>4 5</position>
       <vector>87 78 54 5 -4</vector>
    </agent>
</aaa>

That's my Java code:

这是我的Java代码:

DocumentBuilderFactory documentFactory = DocumentBuilderFactory.newInstance();

DocumentBuilder builder = documentFactory.newDocumentBuilder();
Document document = builder.parse(new File("utility.xml"));

NodeList agents = document.getElementsByTagName("agent");

for(int i=0; i<agents.getLength(); i++) {
        Node node = agents.item(i);

        if(node.getNodeType() == Node.ELEMENT_NODE) {
                Element agente = (Element)node;

                String name = agente.getElementsByTagName("name").item(0).getFirstChild().getNodeValue();
                String position = agente.getElementsByTagName("position").item(0).getFirstChild().getNodeValue();
                String vector = agente.getElementsByTagName("vector").item(0).getFirstChild().getNodeValue();

I want to parse the string position into 2 Integer (4 and 5), and I want to parse the string vector into 5 Integer (and put them into an array). How can I do it? Thank you for your time!

我想将字符串位置解析为2 Integer(4和5),我想将字符串向量解析为5 Integer(并将它们放入数组中)。我该怎么做?感谢您的时间!

2 个解决方案

#1

The logic of converting to int[]

转换为int []的逻辑

public static void main(String args[]) {
    String position ="87 78 54 5 -4";
    String vector = "4 5";

    String[] posArr = position.split(" ");
    int[] positionArray = new int[posArr.length];

    for(int i = 0 ; i < posArr.length ; i ++) {
        positionArray[i] = Integer.parseInt(posArr[i]);
    }

    String[] vectArr = vector.split(" ");
    int[] vectorArray = new int[vectArr.length];
    for(int i = 0 ; i < vectArr.length ; i ++) {
        vectorArray[i] = Integer.parseInt(vectArr[i]);
    }
}

#2

You may use a Scanner and read the contents of the String by using nextInt:

您可以使用Scanner并使用nextInt读取String的内容:

String stringRead = ...; //imagine you read <position> here
Scanner scanner = new Scanner(stringRead);
List<Integer> intList = new ArrayList<>();
while (scanner.hasNext()) {
    intList.add(scanner.nextInt());
}

If you use Java 8, then you can make it shorter by using the power of streams:

如果您使用Java 8,那么您可以通过使用流的强大功能来缩短它:

String stringRead = ...; //imagine you read <position> here
List<Integer> intList = Arrays.stream(stringRead.split("\\s+"))
    .map(x -> Integer.valueOf(x))
    .collect(Collectors.toList());

#1