方法、函数、柯里化
方法
声明方法：
scala> def m1(x:Int,y:Int):Int = {
| x + y
| }
m1: (x: Int, y: Int)Int
scala> m1(3,5)
res6: Int = 8
函数
函数声明
scala> val f1 = (x: Int, y: Int) => x + y
f1: (Int, Int) => Int = <function2> //2是指参数的个数
scala> f1(3,5)
res7: Int = 8
//函数作为参数传入方法
scala> def m2(f: (Int , Int) => Int , x: Int) = f(3,4)
m2: (f: (Int, Int) => Int, x: Int)Int
scala> def m2(f: (Int , Int) => Int , x: Int) = f(3,4) + x
m2: (f: (Int, Int) => Int, x: Int)Int
scala> val f1 = (x: Int, y: Int) => x + y
f1: (Int, Int) => Int = <function2>
scala> m2(f1,2)
res8: Int = 9
//方法转换为函数
方法转换为函数
scala> def m2(f: (Int , Int) => Int , x: Int) = f(3,4)
m2: (f: (Int, Int) => Int, x: Int)Int
scala> def m1(x:Int,y:Int):Int = x + y
m1: (x: Int, y: Int)Int
scala> val f1 = m1 _ //方法m1转换为函数
f1: (Int, Int) => Int = <function2>
scala> m2(f1,2)
res9: Int = 9
scala> m2(m1,2) //m1隐式转换为函数了
res10: Int = 9
柯里化
柯里化（Currying）是把接受多个参数的函数变换成接受一个单一参数(最初函数的第一个参数)的函数，并且返回接受余下的参数且返回结果的新函数的技术
声明方法
// 声明方式1
scala> def currying(x: Int)(y:Int) = x*y
currying: (x: Int)(y: Int)Int
scala> currying(3)(4)
res0: Int = 12
scala> val curry = currying(3)_
curry: Int => Int = <function1>
scala> curry(2)
res1: Int = 6
scala> curry(9)
res2: Int = 27
// 声明方式2
scala> def curry(x: Int) = (y: Int) => x * y
curry: (x: Int)Int => Int
scala> val fun = curry(2)
fun: Int => Int = <function1>
scala> fun(2)
res10: Int = 4
柯里化设置隐式的值
scala> def m2(x: Int)(implicit y: Int = 5) = x * y
m2: (x: Int)(implicit y: Int)Int
scala> m2(5)
res3: Int = 25
scala> m2(4)(4)
res4: Int = 16
scala> implicit val a = 100
a: Int = 100
scala> m2(4)
res5: Int = 400
scala> m2(4)(10)
res6: Int = 40
scala> implicit val b = 200
b: Int = 200
scala> m2(4)
<console>:11: error: ambiguous implicit values:
both value a of type => Int
and value b of type => Int
match expected type Int
m2(4)
^