Ruby类初始化（构造函数）是私有方法还是公共方法？

Is initialize method (constructor) private or public in ruby?

在ruby中初始化方法（构造函数）是私有的还是公共的？

2 个解决方案

#1

Let's see:

让我们来看看：

class Test
  def initialize; end
end

p Test.new.private_methods.sort.include?(:initialize)

This prints true, so initialize is a private method. This makes sense, it is only called by the new class method if the object is created. If we want, we can do something like this:

这打印为true，因此initialize是一个私有方法。这是有道理的，只有在创建对象时才会被新类方法调用。如果我们想要，我们可以这样做：

class Test
  def initialize
    @counter = 0
  end

  def reset!
    initialize
  end
end

Misusing the constructor like this could however lead to problems if it does more than simple variable initialization.

如果它不仅仅是简单的变量初始化，那么滥用这样的构造函数可能会导致问题。

#2

The initialize method in a class automatically becomes Private.

类中的initialize方法自动变为Private。

You can check it using:

您可以使用以下方式检查：

puts ClassName.private_methods.sort

#1