I'm trying to initialize an unsigned long long int type. But the compiler is throwing an error
我正在尝试初始化unsigned long long int类型。但编译器抛出错误
"error: integer constant is too large for "long" type ".
“错误：整数常量对于”long“类型来说太大了”。
The initialization is shown below :
初始化如下所示：
unsigned long long temp = 1298307964911120440;
Can anybody please let me know what the problem is and suggest a solution for the same.
任何人都可以让我知道问题是什么，并提出相同的解决方案。
3 个解决方案
#1
20
Try suffixing your literal value with ULL
尝试使用ULL为您的文字值添加后缀
#2
11
First, be sure your compiler supports the long long type. Second, add a "ULL" suffix to the number.
首先，确保您的编译器支持long long类型。其次，为数字添加“ULL”后缀。
#3
5
Q: How to initialize an unsigned long long type?
问：如何初始化unsigned long long类型？
A: With an unsigned long long constant!
答：使用无符号长长常数！
(Add suffix ULL to the constant.)
（将后缀ULL添加到常量。）
#1
20
Try suffixing your literal value with ULL
尝试使用ULL为您的文字值添加后缀
#2
11
First, be sure your compiler supports the long long type. Second, add a "ULL" suffix to the number.
首先，确保您的编译器支持long long类型。其次，为数字添加“ULL”后缀。
#3
5
Q: How to initialize an unsigned long long type?
问：如何初始化unsigned long long类型？
A: With an unsigned long long constant!
答：使用无符号长长常数！
(Add suffix ULL to the constant.)
（将后缀ULL添加到常量。）