I am searching a key in an Array
of Dictionarys
and I want to convert the result value into an Int
value. This is what I tried.
我正在字典数组中搜索一个键,我想将结果值转换为Int值。这就是我所尝试的。
if let result = lasrIDArray.flatMap( {$0["\(self.selectedTitle)"]} ).first {
print(result)
if let number = result as? NSNumber {
let tag = number.integerValue
let currentScroll = view.viewWithTag(Int(api.selectedCatID)!) as! UIScrollView
let lastImgVw = currentScroll.viewWithTag(tag) as! UIImageView
print(lastImgVw.frame.origin.y)
}
}
But if let number = result as? NSNumber
doesn't work as expected. What is the correct way to convert this value?
但是如果让数字=结果?NSNumber没有按预期工作。转换这个值的正确方法是什么?
3 个解决方案
#1
11
I don't know your code but this will be helpful for you.
我不知道你的密码,但这对你有帮助。
You can get your AnyObject value in this way...
您可以通过这种方式获取AnyObject值……
let data :AnyObject = "100"
let score = Int(data as! String)! //Force Unwrap optional value it will be dengerious for nil condition.
print(score)
Or try this way also
或者也试试这个方法
let hitCount = "100"
let data :AnyObject = hitCount as AnyObject //sometime Xcode will ask value type
let score = Int(data as? String ?? "") ?? 0
print(score)
Output -
Swift 3.1 & Swift 4
let hitCount = "100"
let data :Any = hitCount //Any type Value passing here
let score = Int(data as? String ?? "") ?? 0
print(score)
Output -
#2
0
Here i have given example to convert Anyobject to Int and String
这里我给出了将Anyobject转换为Int和String的示例
var idInt : Int = 0
if let ids: AnyObject = responseDict["id"] {
if let idsInt = ids as? Int{
idInt = idsInt
print(idInt)
}
}
var nameString : String = ""
if let name: AnyObject = responseDict["name"] {
if let nameStr = name as? String{
nameString = nameStr
print(nameString)
}
}
#3
0
If your data is decoded from JSON string, it will be decoded as NSNumber or NSString.
如果您的数据是从JSON字符串解码的,那么它将被解码为NSNumber或NSString。
You can use this function:
你可以使用这个功能:
func intValueForKey(key: String, inDictionary dictionary: [String: AnyObject]) throws -> Int {
if let value = dictionary[key]?.integerValue {
return value
} else {
throw NSError(domain: "Invalid key", code: -1, userInfo: nil)
}
}
#1
11
I don't know your code but this will be helpful for you.
我不知道你的密码,但这对你有帮助。
You can get your AnyObject value in this way...
您可以通过这种方式获取AnyObject值……
let data :AnyObject = "100"
let score = Int(data as! String)! //Force Unwrap optional value it will be dengerious for nil condition.
print(score)
Or try this way also
或者也试试这个方法
let hitCount = "100"
let data :AnyObject = hitCount as AnyObject //sometime Xcode will ask value type
let score = Int(data as? String ?? "") ?? 0
print(score)
Output -
Swift 3.1 & Swift 4
let hitCount = "100"
let data :Any = hitCount //Any type Value passing here
let score = Int(data as? String ?? "") ?? 0
print(score)
Output -
#2
0
Here i have given example to convert Anyobject to Int and String
这里我给出了将Anyobject转换为Int和String的示例
var idInt : Int = 0
if let ids: AnyObject = responseDict["id"] {
if let idsInt = ids as? Int{
idInt = idsInt
print(idInt)
}
}
var nameString : String = ""
if let name: AnyObject = responseDict["name"] {
if let nameStr = name as? String{
nameString = nameStr
print(nameString)
}
}
#3
0
If your data is decoded from JSON string, it will be decoded as NSNumber or NSString.
如果您的数据是从JSON字符串解码的,那么它将被解码为NSNumber或NSString。
You can use this function:
你可以使用这个功能:
func intValueForKey(key: String, inDictionary dictionary: [String: AnyObject]) throws -> Int {
if let value = dictionary[key]?.integerValue {
return value
} else {
throw NSError(domain: "Invalid key", code: -1, userInfo: nil)
}
}