Basically i have a few parents that have the same class:
基本上我有一些同一类的父母:
<div class="parent">
<div class="child"></div>
</div>
<div class="parent">
<div class="child"></div>
</div>
<div class="parent">
<div class="child"></div>
</div>
And when i click on a parent
class i want to toggle its child. For that i'm using:
当我点击父类时,我想切换它的孩子。为此我正在使用:
$(document).ready(function(){
$('.parent').click(function(e){
$(this).children('.child').toggle();
});
});
This does toggle my child but if i leave it visible and i click on the next parent i want to make all other children disappear.
这确实切换了我的孩子,但如果我让它可见,我点击下一个父母我想让所有其他孩子消失。
Is this possible using only jquery/javascript? Thank you!
这可能只使用jquery / javascript吗?谢谢!
3 个解决方案
#1
3
You could use a class to manage display and just toggle that class on current parent and remove it from others
您可以使用类来管理显示,只需在当前父级上切换该类,并将其从其他父级中删除
$('.parent').click(function(){
$('.active').not(this).removeClass('active');
$(this).toggleClass('active');
})
.parent{ margin-bottom:2em}
.child{display:none}
.active .child{ display:block}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="parent">Parent 1
<div class="child">Child</div>
</div>
<div class="parent">Parent 2
<div class="child">Child</div>
</div>
<div class="parent">Parent 3
<div class="child">Child</div>
</div>
#2
1
I think you need to show only one of childs. To do this work first hide all childs then show clicked child.
我想你只需要展示一个孩子。要完成这项工作,首先要隐藏所有孩子,然后显示点击的孩子。
$('.parent').click(function(e){
$(this).siblings().children('.child:visible').toggle();
$(this).children('.child').toggle();
}).children(".child").toggle();
$('.parent').click(function(e){
$(this).siblings().children('.child:visible').slideUp();
$(this).children('.child').slideDown();
}).children(".child").slideUp();
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="parent">parent1
<div class="child">child1</div>
</div>
<div class="parent">parent2
<div class="child">child2</div>
</div>
<div class="parent">parent3
<div class="child">child3</div>
</div>
#3
0
Please Try This:-
请试试这个: -
$('.parent').click(function(e){
if($(this).children('.child').is(':visible')){
$(this).children('.child').slideUp();
}else{
$('.parent .child').slideUp();
$(this).children('.child').slideDown();
}
});
#1
3
You could use a class to manage display and just toggle that class on current parent and remove it from others
您可以使用类来管理显示,只需在当前父级上切换该类,并将其从其他父级中删除
$('.parent').click(function(){
$('.active').not(this).removeClass('active');
$(this).toggleClass('active');
})
.parent{ margin-bottom:2em}
.child{display:none}
.active .child{ display:block}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="parent">Parent 1
<div class="child">Child</div>
</div>
<div class="parent">Parent 2
<div class="child">Child</div>
</div>
<div class="parent">Parent 3
<div class="child">Child</div>
</div>
#2
1
I think you need to show only one of childs. To do this work first hide all childs then show clicked child.
我想你只需要展示一个孩子。要完成这项工作,首先要隐藏所有孩子,然后显示点击的孩子。
$('.parent').click(function(e){
$(this).siblings().children('.child:visible').toggle();
$(this).children('.child').toggle();
}).children(".child").toggle();
$('.parent').click(function(e){
$(this).siblings().children('.child:visible').slideUp();
$(this).children('.child').slideDown();
}).children(".child").slideUp();
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="parent">parent1
<div class="child">child1</div>
</div>
<div class="parent">parent2
<div class="child">child2</div>
</div>
<div class="parent">parent3
<div class="child">child3</div>
</div>
#3
0
Please Try This:-
请试试这个: -
$('.parent').click(function(e){
if($(this).children('.child').is(':visible')){
$(this).children('.child').slideUp();
}else{
$('.parent .child').slideUp();
$(this).children('.child').slideDown();
}
});