将Char转换为C中的字符串。

How do I convert a character to a string in C. I'm currently using c = fgetc(fp) which returns a character. But I need a string to be used in strcpy

我如何将一个字符转换成c中的字符串，我现在使用的是返回一个字符的c = fgetc(fp)。但是我需要一个字符串在strcpy中使用。

9 个解决方案

#1

To answer the question without reading too much else into it i would

为了回答这个问题，我不需要过多的阅读。

char str[2] = "\0"; /* gives {\0, \0} */
str[0] = fgetc(fp);

You could use the second line in a loop with what ever other string operations you want to keep using char's as strings.

您可以使用循环中的第二行来使用其他字符串操作，您希望继续使用char作为字符串。

#2

Using fgetc(fp) only to be able to call strcpy(buffer,c); doesn't seem right.

使用fgetc(fp)只能调用strcpy(缓冲区，c);似乎不正确。

You could simply build this buffer on your own:

您可以自己构建这个缓冲区:

char buffer[MAX_SIZE_OF_MY_BUFFER];

int i = 0;
char ch;
while (i < MAX_SIZE_OF_MY_BUFFER - 1 && (ch = fgetc(fp)) != EOF) {
    buffer[i++] = ch;
}
buffer[i] = '\0';  // terminating character

Note that this relies on the fact that you will read less than MAX_SIZE_OF_MY_BUFFER characters

注意，这依赖于您将读取小于MAX_SIZE_OF_MY_BUFFER字符的事实。

#3

A code like that should work:

这样的代码应该可以工作:

int i = 0;
char string[256], c;
while(i < 256 - 1 && (c = fgetc(fp) != EOF)) //Keep space for the final \0
{
    string[i++] = c;
}
string[i] = '\0';

#4

You could do many of the given answers, but if you just want to do it to be able to use it with strcpy, then you could do the following:

你可以做很多给定的答案，但是如果你只是想用它来用strcpy，那么你可以这样做:

...
    strcpy( ... , (char[2]) { (char) c, '\0' } );
...

The (char[2]) { (char) c, '\0' } part will temporarily generate null-terminated string out of a character c.

(char[2]) {(char) c， '\0'}部分将临时地从字符c中生成以null结尾的字符串。

This way you could avoid creating new variables for something that you already have in your hands, provided that you'll only need that single-character string just once.

通过这种方式，您可以避免为已经掌握在您手中的东西创建新的变量，前提是您只需要一个单字符字符串。

#5

I use this to convert char to string (an example) :

我使用它将char转换为string(示例):

char c = 'A';
char str1[2] = {c , '\0'};
char str2[5] = "";
strcpy(str2,str1);

#6

This is an old question, but I'd say none of the answers really fits the OP's question. All he wanted/needed to do is this:

这是一个老问题，但我认为没有一个答案能真正符合OP的问题。他所要做的就是:

char c = std::fgetc(fp);
std::strcpy(buffer, &c);

The relevant aspect here is the fact, that the second argument of strcpy() doesn't need to be a char array / c-string. In fact, none of the arguments is a char or char array at all. They are both char pointers:

这里的相关方面是，strcpy()的第二个参数不需要是char数组/ c-string。实际上，所有参数都不是char或char。它们都是char指针:

strcpy(char* dest, const char* src);

dest : A non-const char pointer

Its value has to be the memory address of an element of a writable char array (with at least one more element after that).

src : A const char pointer

Its value can be the address of a single char, or of an element in a char array. That array must contain the special character \0 within its remaining elements (starting with src), to mark the end of the c-string that should be copied.

#7

FYI you dont have string datatype in C. Use array of characters to store the value and manipulate it. Change your variable c into an array of characters and use it inside a loop to get values.

在c中没有字符串数据类型，使用字符数组来存储和操作该值。将变量c更改为一个字符数组，并在循环中使用它来获取值。

char c[10];
int i=0;
while(i!=10)
{
    c[i]=fgetc(fp);
    i++;
}

The other way to do is to use pointers and allocate memory dynamically and assign values.

另一种方法是使用指针并动态分配内存和赋值。

#8

//example
char character;//to be scanned
char merge[2];// this is just temporary array to merge with      
merge[0] = character;
merge[1] = '\0';
//now you have changed it into a string

#9

Here is a working exemple :

这里有一个工作例子:

printf("-%s-", (char[2]){'A', 0});

This will display -A-

这将显示——

#1