Here is the code and I don't seem to find what's wrong with it; I need to overload the << and >> operators, but I get the following error:
这是代码,我似乎没有发现它有什么问题;我需要重载< <和> >操作符,但我有以下错误:
Use of overloaded operator '>>' is ambiguous (with operand types 'istream' (aka 'basic_istream') and 'MyIncreEx')
重载运算符>>的使用是不明确的(有操作数类型的istream(又名“basic_istream”)和“MyIncreEx”)
I can't see what's really ambiguous about it:
我看不出这有什么不明确的地方:
#include<iostream>
using namespace std;
class MyIncreEx;
istream& operator>>(istream& is, MyIncreEx& s);
ostream& operator<<(ostream &os, MyIncreEx& s);
MyIncreEx operator++(MyIncreEx& d, int dummy);
MyIncreEx operator++(MyIncreEx& d);
class MyIncreEx
{
friend istream& operator>>(istream& is, MyIncreEx s);
friend ostream& operator<<(ostream& os, MyIncreEx s);
friend MyIncreEx operator++(MyIncreEx& d, int dummy); //post-fix ex: x++;
friend MyIncreEx operator++(MyIncreEx& d); //pre-fix ex: ++x;
public:
MyIncreEx(){num1=0; num2=0; num3=0;};
int num1;
int num2;
int num3;
};
//------------------------------------------------
istream& operator>>(istream& is, MyIncreEx& s)
{
is >> s.num1;
is >> s.num2;
is >> s.num3;
return is;
};
//------------------------------------------------
ostream& operator<<(ostream &os, MyIncreEx& s)
{
os << "(" << s.num1 <<"," <<s.num2 << "," << s.num3 <<")"<< endl;
return os;
};
//------------------------------------------------
MyIncreEx operator++(MyIncreEx& d) //pre-fix ex: ++x;
{
d.num1=d.num1+1;
d.num2=d.num2+1;
d.num3=d.num3+1;
return d;
};
//------------------------------------------------
MyIncreEx operator++(MyIncreEx& d, int dummy) //post-fix ex: x++;
{
d.num1=d.num1+1;
d.num2=d.num2+1;
d.num3=d.num3+1;
return d;
};
//------------------------------------------------
int main()
{
MyIncreEx obj;
cout << "please enter three numbers: ";
cin >> obj;
cout << "The original value are: ";
cout << obj;
cout << endl;
obj++;
cout << "The new values after obj++ are: ";
cout << obj;
cout << endl;
++obj;
cout << "The new values after ++obj are: ";
cout << obj;
cout << endl;
}
//------------------------------------------------
1 个解决方案
#1
3
You declared two different versions of the output operators:
您声明了输出操作符的两个不同版本:
istream& operator>>(istream& is, MyIncreEx& s);
ostream& operator<<(ostream &os, MyIncreEx& s);
class MyIncreEx
{
friend istream& operator>>(istream& is, MyIncreEx s);
friend ostream& operator<<(ostream& os, MyIncreEx s);
...
};
The friend
operators have a different and conflicting signature. You probably wanted to declare them as
朋友操作符有一个不同的、相互冲突的签名。您可能想要声明它们为。
friend istream& operator>>(istream& is, MyIncreEx& s);
friend ostream& operator<<(ostream& os, MyIncreEx const& s);
(assuming you also fix the output operator to work with MyIncreEx const&
rather than MyIncreEx&
).
(假设您还修复了输出操作符以使用MyIncreEx const&而不是MyIncreEx&)。
#1
3
You declared two different versions of the output operators:
您声明了输出操作符的两个不同版本:
istream& operator>>(istream& is, MyIncreEx& s);
ostream& operator<<(ostream &os, MyIncreEx& s);
class MyIncreEx
{
friend istream& operator>>(istream& is, MyIncreEx s);
friend ostream& operator<<(ostream& os, MyIncreEx s);
...
};
The friend
operators have a different and conflicting signature. You probably wanted to declare them as
朋友操作符有一个不同的、相互冲突的签名。您可能想要声明它们为。
friend istream& operator>>(istream& is, MyIncreEx& s);
friend ostream& operator<<(ostream& os, MyIncreEx const& s);
(assuming you also fix the output operator to work with MyIncreEx const&
rather than MyIncreEx&
).
(假设您还修复了输出操作符以使用MyIncreEx const&而不是MyIncreEx&)。