如何按长度对字符串数组排序?

So, I want to sort array of strings by length (longer strings goes first) and if length is the same, then sort alphabetically. This is what is got so far:

所以，我想按长度对字符串数组排序(长字符串优先)如果长度相同，那么按字母顺序排序。这就是目前所得到的:

uses
  System.Generics.Defaults
  , System.Types
  , System.Generics.Collections
  ;

procedure TForm2.FormCreate(Sender: TObject);
var
  _SortMe: TStringDynArray;
begin
  _SortMe := TStringDynArray.Create('abc', 'zwq', 'Long', 'longer');

  TArray.Sort<string>(_SortMe, TDelegatedComparer<string>.Construct(
    function(const Left, Right: string): Integer
    begin
      Result := CompareText(Left, Right);
    end));
end;

Expected result: longer, Long, abc, zwq

期望结果:长，长，abc, zwq。

2 个解决方案

#1

Adjusting your anonymous function:

调整你的匿名函数:

function(const Left, Right: string): Integer
    begin
      //Compare by Length, reversed as longest shall come first
      Result := CompareValue(Right.Length, Left.Length);
      if Result = EqualsValue then
        Result := CompareText(Left, Right);
    end));

You'll need to add System.Math and System.SysUtils to your uses.

您需要添加系统。数学和系统。SysUtils使用。

#2

I would have used a TStringList for this...

我会用一个TStringList…

Any way, just customize the comparison function:

无论如何，只需自定义比较函数:

  TArray.Sort<string>(_SortMe, TDelegatedComparer<string>.Construct(
    function(const Left, Right: string): Integer
    begin
      Result := length(Right) - length(Left); // compare by decreasing length
      if Result = 0 then
        Result := CompareText(Left, Right);  // compare alphabetically
    end));

#1