I have the following table
我有下表
CREATE TABLE Test
(`Id` int, `value` varchar(20), `adate` varchar(20))
;
INSERT INTO Test
(`Id`, `value`, `adate`)
VALUES
(1, 100, '2014-01-01'),
(1, 200, '2014-01-02'),
(1, 300, '2014-01-03'),
(2, 200, '2014-01-01'),
(2, 400, '2014-01-02'),
(2, 30 , '2014-01-04'),
(3, 800, '2014-01-01'),
(3, 300, '2014-01-02'),
(3, 60 , '2014-01-04')
;
I want to achieve the result which selects only Id having max value of date. ie
我想实现只选择具有最大日期值的Id的结果。即
Id ,value ,adate
Id,价值,adate
1, 300,'2014-01-03'
2, 30 ,'2014-01-04'
3, 60 ,'2014-01-04'
how can I achieve this using group by
? I have done as follows but it is not working.
我如何使用group by实现这一目标?我做了如下但不起作用。
Select Id,value,adate
from Test
group by Id,value,adate
having adate = MAX(adate)
Can someone help with the query?
有人可以帮助查询吗?
4 个解决方案
#1
3
If you are using a DBMS that has analytical functions you can use ROW_NUMBER:
如果您使用的是具有分析功能的DBMS,则可以使用ROW_NUMBER:
SELECT Id, Value, ADate
FROM ( SELECT ID,
Value,
ADate,
ROW_NUMBER() OVER(PARTITION BY ID ORDER BY Adate DESC) AS RowNum
FROM Test
) AS T
WHERE RowNum = 1;
Otherwise you will need to use a join to the aggregated max date by Id to filter the results from Test
to only those where the date matches the maximum date for that Id
否则,您需要使用连接到ID的聚合最大日期,以便将测试结果过滤到日期与该Id的最大日期匹配的结果
SELECT Test.Id, Test.Value, Test.ADate
FROM Test
INNER JOIN
( SELECT ID, MAX(ADate) AS ADate
FROM Test
GROUP BY ID
) AS MaxT
ON MaxT.ID = Test.ID
AND MaxT.ADate = Test.ADate;
#2
9
Select the maximum dates for each id.
选择每个ID的最大日期。
select id, max(adate) max_date
from test
group by id
Join on that to get the rest of the columns.
加入其中以获得其余列。
select t1.*
from test t1
inner join (select id, max(adate) max_date
from test
group by id) t2
on t1.id = t2.id and t1.adate = t2.max_date;
#3
2
Please try:
请尝试:
select
*
from
tbl a
where
a.adate=(select MAX(adate) from tbl b where b.Id=a.Id)
#4
-1
I would try something like this
我会尝试这样的事情
Select t1.Id, t1.value, t1.adate
from Test as t1
where t1.adate = (select max(t2.adate)
from Test as t2
where t2.id = t1.id)
#1
3
If you are using a DBMS that has analytical functions you can use ROW_NUMBER:
如果您使用的是具有分析功能的DBMS,则可以使用ROW_NUMBER:
SELECT Id, Value, ADate
FROM ( SELECT ID,
Value,
ADate,
ROW_NUMBER() OVER(PARTITION BY ID ORDER BY Adate DESC) AS RowNum
FROM Test
) AS T
WHERE RowNum = 1;
Otherwise you will need to use a join to the aggregated max date by Id to filter the results from Test
to only those where the date matches the maximum date for that Id
否则,您需要使用连接到ID的聚合最大日期,以便将测试结果过滤到日期与该Id的最大日期匹配的结果
SELECT Test.Id, Test.Value, Test.ADate
FROM Test
INNER JOIN
( SELECT ID, MAX(ADate) AS ADate
FROM Test
GROUP BY ID
) AS MaxT
ON MaxT.ID = Test.ID
AND MaxT.ADate = Test.ADate;
#2
9
Select the maximum dates for each id.
选择每个ID的最大日期。
select id, max(adate) max_date
from test
group by id
Join on that to get the rest of the columns.
加入其中以获得其余列。
select t1.*
from test t1
inner join (select id, max(adate) max_date
from test
group by id) t2
on t1.id = t2.id and t1.adate = t2.max_date;
#3
2
Please try:
请尝试:
select
*
from
tbl a
where
a.adate=(select MAX(adate) from tbl b where b.Id=a.Id)
#4
-1
I would try something like this
我会尝试这样的事情
Select t1.Id, t1.value, t1.adate
from Test as t1
where t1.adate = (select max(t2.adate)
from Test as t2
where t2.id = t1.id)