SQL Server使用不同的排序规则查询两个链接的数据库

时间:2022-03-13 15:40:11

I've got 2 remote databases as part of a query

我有2个远程数据库作为查询的一部分

select p.ID,p.ProjectCode_VC,p.Name_VC,v.*
FROM [serverB].Projects.dbo.Projects_T p
LEFT JOIN [serverA].SOCON.dbo.vw_PROJECT v on
p.ProjectCode_VC = v.PROJ_CODE

The problem is that serverA uses collation Latin1_General_BIN and serverB uses Latin1_General_CP1_CP_AS and the query refuses to run.

问题是serverA使用排序规则Latin1_General_BIN而serverB使用Latin1_General_CP1_CP_AS并且查询拒绝运行。

Both servers are SQL 2000 servers. Both databases are set in stone so I cannot change their collations, unfortunately.

两台服务器都是SQL 2000服务器。两个数据库都是一成不变的,所以不幸的是我无法更改它们的排序规则。

Is there anyway you guys know how to get this to work?

无论如何你们都知道如何让它发挥作用吗?

Update: I found an alternative solution. In the Linked Server Properties, you can specify the linked server's collation there.

更新:我找到了另一种解决方案。在“链接服务器属性”中,您可以在那里指定链接服务器的排序规则。

2 个解决方案

#1


9  

Just add the collation to your select, like:

只需将排序规则添加到您的选择中,例如:

select 
  p.ID,
  p.ProjectCode_VC,
  p.Name_VC,
  v.* 
FROM
  [serverB].Projects.dbo.Projects_T p 
  LEFT JOIN [serverA].SOCON.dbo.vw_PROJECT v on p.ProjectCode_VC 
    collate Latin1_General_Bin = v.PROJ_CODE

or the other way around. So "convert" one of the collations to the other.

或者相反。因此,将其中一个归类“转换”为另一个归类。

#2


2  

Or you can use a more generic query like this:

或者您可以使用这样的更通用的查询:

select * from profile, userinfo
where profile.custid collate database_default = userinfo.custid collate database_default

#1


9  

Just add the collation to your select, like:

只需将排序规则添加到您的选择中,例如:

select 
  p.ID,
  p.ProjectCode_VC,
  p.Name_VC,
  v.* 
FROM
  [serverB].Projects.dbo.Projects_T p 
  LEFT JOIN [serverA].SOCON.dbo.vw_PROJECT v on p.ProjectCode_VC 
    collate Latin1_General_Bin = v.PROJ_CODE

or the other way around. So "convert" one of the collations to the other.

或者相反。因此,将其中一个归类“转换”为另一个归类。

#2


2  

Or you can use a more generic query like this:

或者您可以使用这样的更通用的查询:

select * from profile, userinfo
where profile.custid collate database_default = userinfo.custid collate database_default