如何搜索与strpos的特定单词的数组?

$data = "
usera: Lorem ipsum dolor sit amet, consetetur sadipscing elitr, sed diam nonumy.
userb: eirmod tempor invidunt ut labore et dolore magna aliquyam erat, sed diam.
userc:voluptua. At vero eos et accusam et justo duo dolores et ea rebum. Stet.";

preg_match_all("/(.*:)/", $data, $why1);
array_walk_recursive($why1, function($value) use (&$why2) {
    $why2[] = $value;
});
$why3 = array_unique($why2);
$why4 = array_values($why3);

preg_match_all("/(.*.)/", $data, $info);
array_walk_recursive($info, function($value) use (&$shrink) {
    $shrink[] = $value;
});
$brss = array_unique($array_flat);
$arss = array_values($brss);

for($i=0;$i < count($brss); $i++){

$usera = "$why4[0]";
$userb = "$why4[1]";
$userc = "$why4[2]";
$userd = "$why4[3]";

if (strpos($brss[i], $usera) !== false) 

// How can I
{echo "true";}
// ?

// I only get false

else {echo "false";}

}

How to get a true in searching my array by asking a specific word with strpos?

如何通过向strpos询问一个特定的单词来实现对数组的搜索?

How can I echo "true";?

我如何回应“真实”?

1 个解决方案

#1

if (strpos($brss[**$i**],$usera)!==false) {
    echo "true";
} else {
    echo "false";
}

Does it.

它。