如何使用Python从RESTful服务获得JSON数据?

Is there any standard way of getting JSON data from RESTful service using Python?

有使用Python从RESTful服务获取JSON数据的标准方法吗?

I need to use kerberos for authentication.

我需要使用kerberos进行身份验证。

some snippet would help.

一些片段会有所帮助。

5 个解决方案

#1

Something like this should work unless I'm missing the point:

像这样的东西应该有用，除非我没抓住要点:

import json
import urllib2
json.load(urllib2.urlopen("url"))

#2

106

I would give the requests library a try for this. Essentially just a much easier to use wrapper around the standard library modules (i.e. urllib2, httplib2, etc.) you would use for the same thing. For example, to fetch json data from a url that requires basic authentication would look like this:

我想尝试一下请求库。基本上，在标准库模块(例如urllib2、httplib2等)周围使用包装器要容易得多，您也可以使用它们。例如，从需要基本身份验证的url获取json数据的方式如下:

import requests

response = requests.get('http://thedataishere.com',
                         auth=('user', 'password'))
data = response.json()

For kerberos authentication the requests project has the reqests-kerberos library which provides a kerberos authentication class that you can use with requests:

对于kerberos身份验证，请求项目具有reqester -kerberos库，该库提供一个kerberos身份验证类，您可以在请求时使用:

import requests
from requests_kerberos import HTTPKerberosAuth

response = requests.get('http://thedataishere.com',
                         auth=HTTPKerberosAuth())
data = response.json()

#3

You basically need to make a HTTP request to the service, and then parse the body of the response. I like to use httplib2 for it:

您基本上需要向服务发出HTTP请求，然后解析响应的主体。我喜欢用httplib2:

import httplib2 as http
import json

try:
    from urlparse import urlparse
except ImportError:
    from urllib.parse import urlparse

headers = {
    'Accept': 'application/json',
    'Content-Type': 'application/json; charset=UTF-8'
}

uri = 'http://yourservice.com'
path = '/path/to/resource/'

target = urlparse(uri+path)
method = 'GET'
body = ''

h = http.Http()

# If you need authentication some example:
if auth:
    h.add_credentials(auth.user, auth.password)

response, content = h.request(
        target.geturl(),
        method,
        body,
        headers)

# assume that content is a json reply
# parse content with the json module
data = json.loads(content)

#4

If you desire to use Python 3, you can use the following:

如果您希望使用Python 3，可以使用以下内容:

import json
import urllib.request
req = urllib.request.Request('url')
with urllib.request.urlopen(req) as response:
    result = json.loads(response.readall().decode('utf-8'))

#5

Well first of all I think rolling out your own solution for this all you need is urllib2 or httplib2 . Anyways in case you do require a generic REST client check this out .

首先，我想你们需要的是urllib2或httplib2。无论如何，如果您确实需要一个通用的REST客户端，请检查一下。

https://github.com/scastillo/siesta

However i think the feature set of the library will not work for most web services because they shall probably using oauth etc .. . Also I don't like the fact that it is written over httplib which is a pain as compared to httplib2 still should work for you if you don't have to handle a lot of redirections etc ..

但是，我认为库的特性集对大多数web服务都不起作用，因为它们可能会使用oauth等。我也不喜欢它是写在httplib上的这和httplib相比很痛苦如果你不需要处理很多重定向，b2仍然适用。

#1