I'm an absolute beginner in using javascript and ajax and that's why I'm stuck now. I have a while loop in which there are 2 different buttons. Both work, as I imagine, except for one little thing ...
我是使用javascript和ajax的绝对初学者,这就是我现在被困住的原因。我有一个while循环,其中有2个不同的按钮。正如我想象的那样,两者都有效,除了一件小事......
The product-id
is always passed only for the first element or, if I change it for the last element. How can I pass the correct product ID to the script?
product-id始终仅针对第一个元素传递,或者如果我为最后一个元素更改它。如何将正确的产品ID传递给脚本?
This is my PHP file:
这是我的PHP文件:
<?php while ( $product = $browse->fetch( PDO::FETCH_ASSOC ) ) :
$postid = $product[ 'id' ];
$userid = 1; ?>
<div id="content_<?php echo $postid ?>">
<div id="reload_<?php echo $postid ?>" class="row postfarbe browse">
<form method='post' action="" onsubmit="return add();">
<input type="hidden" id="userid" value="<?php echo $userid ?>" class="input-box">
<input type="hidden" id="productid" value="<?php echo $postid ?>" class="input-box">
<input type="hidden" id="collection" value="1" class="input-box">
<input type="hidden" id="wish" value="0" class="input-box">
<input type="submit" id="submit" value="Add to Collection" class="btn my-2 my-sm-0 btn-outline-dark btn-sm">
</form>
</div>
</div>
<?php endwhile; ?>
My Javascript is:
我的Javascript是:
function add()
{
var userid = document.getElementById("userid").value;
var productid = document.getElementById("productid").value;
var collection = document.getElementById("collection").value;
var wishlist = document.getElementById("wish").value;
if(userid && productid && collection && wishlist) {
$.ajax
({
type: 'post',
url: 'post_collection.php',
data: {
user_id:userid,
product_id:productid,
collection_id:collection,
wishlist_id:wishlist
},
success: function (response) {
$("#content_"+ productid).load(" #reload_" + productid);
}
});
}
return false;
}
</script>
I know that the product id in my example is always the same, but how can I pass the correct one to the script if there are 10 or more entries in the loop?
我知道我的示例中的产品ID总是相同的,但如果循环中有10个或更多条目,我怎样才能将正确的产品ID传递给脚本?
2 个解决方案
#1
3
Your problem is that id
is unique and can only be assigned once to a element, like so:
您的问题是id是唯一的,只能分配给一个元素,如下所示:
<p id="paragraph"> This is legal </p>
<p id="paragraph"> This is illegal - It is no longer unique </p>
<p class="paragraph"> This is legal </p>
<p class="paragraph"> This is legal </p>
You can access the currently clicked class by using $(this)
like so:
您可以使用$(this)来访问当前单击的类,如下所示:
$('.paragraph').click(function() {
$(this).html('See, totally legal.');
});
See this example to see this in use.
请参阅此示例以查看此内容。
Your solution needs to add an onclick()
method to a button
. This then gets the parent()
form. You can then find()
the class and get the val()
from the form data.
您的解决方案需要向按钮添加onclick()方法。然后获取parent()表单。然后,您可以查找()类并从表单数据中获取val()。
Your form was also submitting the action. You need to have a <button>
of type button
so it does not submit the action. This must also be a class since it will not be unique if you're multiply creating them.
您的表单也提交了该操作。你需要一个类型按钮的
Here is a working example to just re-add your AJAX request too.
这是一个只是重新添加AJAX请求的工作示例。
$(document).ready(function() {
$('.submit-btn').click(function() {
var elements = {
'userid': $(this).parent().find('.userid').val(),
'productid': $(this).parent().find('.productid').val(),
'collection': $(this).parent().find('.collection').val(),
'wish': $(this).parent().find('.wish').val()
};
console.log("User ID: " + elements.userid);
console.log("Product ID: " + elements.productid);
console.log("Collection: " + elements.collection);
console.log("Wish: " + elements.wish);
// TODO: Add your AJAX request using these elements
});
});
button {
background: #0084ff;
border: none;
border-radius: 5px;
padding: 8px 14px;
font-size: 15px;
color: #fff;
cursor: pointer;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<!-- This will be generated by PHP -->
<form method='POST'>
<input hidden class="userid input-box" value="1">
<input hidden class="productid input-box" value="1">
<input hidden class="collection input-box" value="1">
<input hidden class="wish input-box" value="1">
<button type="button" class="submit-btn btn my-2 my-sm-0 btn-outline-dark btn-sm"> Add to collection </button>
</form>
<!-- This will be generated by PHP -->
<br />
<form method='POST'>
<input hidden class="userid input-box" value="2">
<input hidden class="productid input-box" value="2">
<input hidden class="collection input-box" value="2">
<input hidden class="wish input-box" value="2">
<button type="button" class="submit-btn btn my-2 my-sm-0 btn-outline-dark btn-sm"> Add to collection </button>
</form>
Your AJAX Data will look like this:
您的AJAX数据将如下所示:
data: {
user_id: elements.userid,
product_id: elements.productid,
collection_id: elements.collection,
wishlist_id: elements.wish
}
Your PHP code could look like this:
您的PHP代码可能如下所示:
<?php foreach($browse->fetchAll(PDO::FETCH_ASSOC) as $product):
$id = $product['id'];
$productDd = $product['product_id'];
$productCategory = $product['category']; // TODO: change to your column nanme
$productWishList = $product['wish']; ?>
<div class="content_<?= $id; ?>">
<div class="reload_<?= $id; ?> row postfarbe browse">
<form method='POST'>
<input hidden class="userid input-box" value="<?= $id; ?>">
<input hidden class="productid input-box" value="<?= $productCategory; ?>">
<input hidden class="collection input-box" value="<?= $productCollection; ?>">
<input hidden class="wish input-box" value="<?= $productWishList; ?>">
<button type="button" class="submit-btn btn my-2 my-sm-0 btn-outline-dark btn-sm"> Add to collection </button>
</form>
</div>
</div>
<?php endforeach; ?>
#2
0
I read your code , You want to have multiple entries and want to read / fetch dynamically generated Form's Feilds in the common JS Function Add which is currently referring to FIRST FOUND ELEMENT IN RENDERED HTML - Thats the reason you are getting the same value each time.
我读了你的代码,你想拥有多个条目,并且希望在常见的JS函数Add中读取/获取动态生成的Form的Feilds,这个函数目前是指在渲染的HTML中的第一个已发现的元素 - 这就是你每次获得相同值的原因。
You need to alter the logic with little tric - Pass something uniqueness in argument of ADD function
你需要用很少的三元组改变逻辑 - 在ADD函数的参数中传递一些唯一性
<form method='post' action="" onsubmit="return add(<?php echo $postid; ?> );">
<input type="hidden" id="<?php echo $postid; ?>_userid" value="<?php echo $userid ?>" class="input-box">
<input type="hidden" id="<?php echo $postid; ?>_productid" value="<?php echo $postid ?>" class="input-box">
<input type="hidden" id="<?php echo $postid; ?>_collection" value="1" class="input-box">
<input type="hidden" id="<?php echo $postid; ?>_wish" value="0" class="input-box">
<input type="submit" id="<?php echo $postid; ?>_submit" value="Add to Collection" class="btn my-2 my-sm-0 btn-outline-dark btn-sm">
NOW read uniquely in ADD Function
现在在ADD函数中唯一读取
function add(post_id){
var userid = document.getElementById(post_id+"_userid").value;
var productid = document.getElementById(post_id+"_productid").value;
var collection = document.getElementById(post_id+"_collection").value;
var wishlist = document.getElementById(post_id+"_wish").value;
### Your code as it is ...
}
Hope this make you sense How i have generated in Loop Unique ELEMENT ID and pass same ID in the function as Argument to fetch them in JS.
希望这能让你感觉如何在循环唯一元素ID中生成并在函数中传递相同的ID作为Argument以在JS中获取它们。
#1
3
Your problem is that id
is unique and can only be assigned once to a element, like so:
您的问题是id是唯一的,只能分配给一个元素,如下所示:
<p id="paragraph"> This is legal </p>
<p id="paragraph"> This is illegal - It is no longer unique </p>
<p class="paragraph"> This is legal </p>
<p class="paragraph"> This is legal </p>
You can access the currently clicked class by using $(this)
like so:
您可以使用$(this)来访问当前单击的类,如下所示:
$('.paragraph').click(function() {
$(this).html('See, totally legal.');
});
See this example to see this in use.
请参阅此示例以查看此内容。
Your solution needs to add an onclick()
method to a button
. This then gets the parent()
form. You can then find()
the class and get the val()
from the form data.
您的解决方案需要向按钮添加onclick()方法。然后获取parent()表单。然后,您可以查找()类并从表单数据中获取val()。
Your form was also submitting the action. You need to have a <button>
of type button
so it does not submit the action. This must also be a class since it will not be unique if you're multiply creating them.
您的表单也提交了该操作。你需要一个类型按钮的
Here is a working example to just re-add your AJAX request too.
这是一个只是重新添加AJAX请求的工作示例。
$(document).ready(function() {
$('.submit-btn').click(function() {
var elements = {
'userid': $(this).parent().find('.userid').val(),
'productid': $(this).parent().find('.productid').val(),
'collection': $(this).parent().find('.collection').val(),
'wish': $(this).parent().find('.wish').val()
};
console.log("User ID: " + elements.userid);
console.log("Product ID: " + elements.productid);
console.log("Collection: " + elements.collection);
console.log("Wish: " + elements.wish);
// TODO: Add your AJAX request using these elements
});
});
button {
background: #0084ff;
border: none;
border-radius: 5px;
padding: 8px 14px;
font-size: 15px;
color: #fff;
cursor: pointer;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<!-- This will be generated by PHP -->
<form method='POST'>
<input hidden class="userid input-box" value="1">
<input hidden class="productid input-box" value="1">
<input hidden class="collection input-box" value="1">
<input hidden class="wish input-box" value="1">
<button type="button" class="submit-btn btn my-2 my-sm-0 btn-outline-dark btn-sm"> Add to collection </button>
</form>
<!-- This will be generated by PHP -->
<br />
<form method='POST'>
<input hidden class="userid input-box" value="2">
<input hidden class="productid input-box" value="2">
<input hidden class="collection input-box" value="2">
<input hidden class="wish input-box" value="2">
<button type="button" class="submit-btn btn my-2 my-sm-0 btn-outline-dark btn-sm"> Add to collection </button>
</form>
Your AJAX Data will look like this:
您的AJAX数据将如下所示:
data: {
user_id: elements.userid,
product_id: elements.productid,
collection_id: elements.collection,
wishlist_id: elements.wish
}
Your PHP code could look like this:
您的PHP代码可能如下所示:
<?php foreach($browse->fetchAll(PDO::FETCH_ASSOC) as $product):
$id = $product['id'];
$productDd = $product['product_id'];
$productCategory = $product['category']; // TODO: change to your column nanme
$productWishList = $product['wish']; ?>
<div class="content_<?= $id; ?>">
<div class="reload_<?= $id; ?> row postfarbe browse">
<form method='POST'>
<input hidden class="userid input-box" value="<?= $id; ?>">
<input hidden class="productid input-box" value="<?= $productCategory; ?>">
<input hidden class="collection input-box" value="<?= $productCollection; ?>">
<input hidden class="wish input-box" value="<?= $productWishList; ?>">
<button type="button" class="submit-btn btn my-2 my-sm-0 btn-outline-dark btn-sm"> Add to collection </button>
</form>
</div>
</div>
<?php endforeach; ?>
#2
0
I read your code , You want to have multiple entries and want to read / fetch dynamically generated Form's Feilds in the common JS Function Add which is currently referring to FIRST FOUND ELEMENT IN RENDERED HTML - Thats the reason you are getting the same value each time.
我读了你的代码,你想拥有多个条目,并且希望在常见的JS函数Add中读取/获取动态生成的Form的Feilds,这个函数目前是指在渲染的HTML中的第一个已发现的元素 - 这就是你每次获得相同值的原因。
You need to alter the logic with little tric - Pass something uniqueness in argument of ADD function
你需要用很少的三元组改变逻辑 - 在ADD函数的参数中传递一些唯一性
<form method='post' action="" onsubmit="return add(<?php echo $postid; ?> );">
<input type="hidden" id="<?php echo $postid; ?>_userid" value="<?php echo $userid ?>" class="input-box">
<input type="hidden" id="<?php echo $postid; ?>_productid" value="<?php echo $postid ?>" class="input-box">
<input type="hidden" id="<?php echo $postid; ?>_collection" value="1" class="input-box">
<input type="hidden" id="<?php echo $postid; ?>_wish" value="0" class="input-box">
<input type="submit" id="<?php echo $postid; ?>_submit" value="Add to Collection" class="btn my-2 my-sm-0 btn-outline-dark btn-sm">
NOW read uniquely in ADD Function
现在在ADD函数中唯一读取
function add(post_id){
var userid = document.getElementById(post_id+"_userid").value;
var productid = document.getElementById(post_id+"_productid").value;
var collection = document.getElementById(post_id+"_collection").value;
var wishlist = document.getElementById(post_id+"_wish").value;
### Your code as it is ...
}
Hope this make you sense How i have generated in Loop Unique ELEMENT ID and pass same ID in the function as Argument to fetch them in JS.
希望这能让你感觉如何在循环唯一元素ID中生成并在函数中传递相同的ID作为Argument以在JS中获取它们。