I'm trying to show my latest photos on my website. I used to do it on previous version of Instagram API, but now that it changed I can't.
我想在我的网站上显示我的最新照片。我曾经在之前版本的Instagram API上做过，但现在它改变了我不能。
I created an app on the Instagram Account, and did all authenticate steps as described on the docs, but it always shows me a screen asking for the user login. But I need to show the pictures even the user is not logged, is it possible in this new API version?
我在Instagram帐户上创建了一个应用程序，并按照文档中的描述执行了所有验证步骤，但它始终显示一个要求用户登录的屏幕。但是我需要显示图片，即使用户没有登录，这个新的API版本是否可能？
PS. I'm using PHP on server-side.
PS。我在服务器端使用PHP。
Thanks.
谢谢。
2 个解决方案
#1
1
You can get user's all instagram post by his authentication. Without authentication you can not user's data in new api system. In new api , you can get his post image url and save it in your database. Then you can show image by those url.
您可以通过身份验证获取用户的所有Instagram帖子。没有身份验证，您无法在新的api系统中使用用户的数据。在新的api中，您可以获取他的帖子图像网址并将其保存在您的数据库中。然后你可以通过这些网址显示图像。
#2
1
<?php
function fetchData($url){
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_TIMEOUT, 20);
$result = curl_exec($ch);
curl_close($ch);
return $result;
}
$result = fetchData("https://api.instagram.com/v1/users/ID-GOES-HERE/media/recent/?access_token=TOKEN-GOES-HERE");
$result = json_decode($result);
foreach ($result->data as $post) {
// Do something with this data.
}
?>
资源
#1
1
You can get user's all instagram post by his authentication. Without authentication you can not user's data in new api system. In new api , you can get his post image url and save it in your database. Then you can show image by those url.
您可以通过身份验证获取用户的所有Instagram帖子。没有身份验证，您无法在新的api系统中使用用户的数据。在新的api中，您可以获取他的帖子图像网址并将其保存在您的数据库中。然后你可以通过这些网址显示图像。
#2
1
<?php
function fetchData($url){
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_TIMEOUT, 20);
$result = curl_exec($ch);
curl_close($ch);
return $result;
}
$result = fetchData("https://api.instagram.com/v1/users/ID-GOES-HERE/media/recent/?access_token=TOKEN-GOES-HERE");
$result = json_decode($result);
foreach ($result->data as $post) {
// Do something with this data.
}
?>
资源