如何逃脱knitr的反击?

时间:2021-10-16 14:58:14

I have a variable named statistical value of life in millions of 2006 dollars, and I'm trying to include the value in inline knitr code.

我有一个名为生命统计值的变量,数百万美元,我试图将值包含在内联编织器代码中。

`r `statistical value of life in millions of 2006 dollars` `

I can't figure out how to escape the backticks.

我无法弄清楚如何逃避反击。

2 个解决方案

#1


10  

I think the easiest solution is to use another way of addressing the variable:

我认为最简单的解决方案是使用另一种方式来处理变量:

`r get('statistical value of life in millions of 2006 dollars')`

#2


0  

Perhaps consider using a name without spaces in it (and a little shorter).

也许考虑使用一个没有空格的名称(并且稍微短一点)。

#1


10  

I think the easiest solution is to use another way of addressing the variable:

我认为最简单的解决方案是使用另一种方式来处理变量:

`r get('statistical value of life in millions of 2006 dollars')`

#2


0  

Perhaps consider using a name without spaces in it (and a little shorter).

也许考虑使用一个没有空格的名称(并且稍微短一点)。