I have a table like this:
我有一张这样的桌子:
declare @rooms table
(
depa_key int,
room_key int,
d1 int,
d2 int
)
insert into @rooms(depa_key, room_key, d1, d2)
select 1, null, null, null
union all
select 1, 1, 1, 1
union all
select 1, 1, 1, 1
union all
select 2, null, null, null
union all
select 2, 1, 5, 3
union all
select 2, 1, 7, 2
union all
select 3, null, null, null
union all
select 3, 1, 6, 9
union all
select 3, 1, 5, 8
Table is populated with:
表填充:
What I would like to do (but I don't know how) is populate summary rows (rows where romm_key is null
with summary from that depa_key
.
我想做的(但我不知道怎么做)是填充摘要行(其中romm_key为空的行使用来自depa_key的摘要。
Row where room_key is null is summary row. Only departments does not have room_key (because department means all rooms). Each room has room_key and depa_key.
room_key为null的行是summary行。只有部门没有房间钥匙(因为部门意味着所有的房间)。每个房间都有room_key和depa_key。
Example:
例子:
First row (depa_key = 1, room_key = NULL) should be populated with:
第一行(depa_key = 1, room_key = NULL)应该填充为:
D1 D2
2 2
Second row (depa_key = 2, room_key = NULL) should be populated with:
第二行(depa_key = 2, room_key = NULL)应该填充为:
D1 D2
12 5
There will be a lot of depa_keys in the future (table is changing dynamic), so query must also be dynamic. I could type depa_keys one by one (update queries), but I can't do this. How to update columns d1 and d2 with summaries from that depa_key dynamically?
将来会有很多depa_keys(表是动态变化的),因此查询也必须是动态的。我可以逐个输入depa_keys(更新查询),但是我不能这样做。如何用depa_key中的摘要动态更新d1和d2列?
2 个解决方案
#1
2
Try this out.
试试这个。
declare @rooms table
(
depa_key int,
room_key int,
d1 int,
d2 int
)
insert into @rooms(depa_key, room_key, d1, d2)
select 1, null, null, null
union all
select 1, 1, 1, 1
union all
select 1, 1, 1, 1
union all
select 2, null, null, null
union all
select 2, 1, 5, 3
union all
select 2, 1, 7, 2
union all
select 3, null, null, null
union all
select 3, 1, 6, 9
union all
select 3, 1, 5, 8
UPDATE @rooms
SET d1 = a.d1, d2 = a.d2
FROM (
SELECT depa_key, SUM(D1)d1, SUM(d2) d2
FROM @rooms
GROUP BY depa_key
) a
JOIN @rooms r ON
a.depa_key = r.depa_key
WHERE r.room_key IS NULL
SELECT *
FROM @rooms
#2
1
The solution with CTE looks more readable. At first we take aggregated information for depa_key
taking only records for rooms where room_key IS NOT NULL
. Then we update rows where room_key IS NULL
by this aggregated data.
CTE的解决方案看起来更具有可读性。首先,我们获取depa_key的聚合信息,只获取room_key不为空的房间的记录。然后更新room_key为NULLby的行。
;WITH DepaStats AS
(
SELECT
depa_key AS depa_key,
SUM(d1) AS sum_d1,
SUM(d2) AS sum_d2
FROM @rooms
WHERE room_key IS NOT NULL
GROUP BY depa_key
)
UPDATE R
SET
d1 = S.sum_d1,
d2 = S.sum_d2
FROM @rooms R
LEFT JOIN DepaStats S
ON S.depa_key = R.depa_key
WHERE R.room_key IS NULL
#1
2
Try this out.
试试这个。
declare @rooms table
(
depa_key int,
room_key int,
d1 int,
d2 int
)
insert into @rooms(depa_key, room_key, d1, d2)
select 1, null, null, null
union all
select 1, 1, 1, 1
union all
select 1, 1, 1, 1
union all
select 2, null, null, null
union all
select 2, 1, 5, 3
union all
select 2, 1, 7, 2
union all
select 3, null, null, null
union all
select 3, 1, 6, 9
union all
select 3, 1, 5, 8
UPDATE @rooms
SET d1 = a.d1, d2 = a.d2
FROM (
SELECT depa_key, SUM(D1)d1, SUM(d2) d2
FROM @rooms
GROUP BY depa_key
) a
JOIN @rooms r ON
a.depa_key = r.depa_key
WHERE r.room_key IS NULL
SELECT *
FROM @rooms
#2
1
The solution with CTE looks more readable. At first we take aggregated information for depa_key
taking only records for rooms where room_key IS NOT NULL
. Then we update rows where room_key IS NULL
by this aggregated data.
CTE的解决方案看起来更具有可读性。首先,我们获取depa_key的聚合信息,只获取room_key不为空的房间的记录。然后更新room_key为NULLby的行。
;WITH DepaStats AS
(
SELECT
depa_key AS depa_key,
SUM(d1) AS sum_d1,
SUM(d2) AS sum_d2
FROM @rooms
WHERE room_key IS NOT NULL
GROUP BY depa_key
)
UPDATE R
SET
d1 = S.sum_d1,
d2 = S.sum_d2
FROM @rooms R
LEFT JOIN DepaStats S
ON S.depa_key = R.depa_key
WHERE R.room_key IS NULL